CHEMISTRY COMMUNITY

Catherine_L_1C

R(8.314) times T(298) divided by F (96485.3) should give you 0.02567823285, which is slightly off from what the answer key says, but should be acceptable for the following calculations. I believe on some of the equation sheets we were given with our course readers Faraday's constant looks like 96485...

Catherine_L_1C

Even if isn't present in the overall reaction, if the catalyst is present in the rate limiting step, it should still be included in the rate of reaction equation. Remember though that catalysts don't change the reaction's equilibrium so they aren't included in calculations for the equilibrium consta...

Catherine_L_1C

I think the phrasing is referring to the fact that if you started numbering at the other end the methyl substituent would be at position 3 and the ethyl substituent at 5, so there are 2 constituents both at the 3 or 5 position either way you start from (making them "equivalent"). The examp...

Catherine_L_1C

\frac{d[A]}{[A]} can be manipulated to \int \frac{1}{[A]} d[A] , and after integrating that you would get \ln [A] , which is a standard integral I think we're just supposed to memorize. There are different rules for finding derivatives, but I don't think we have to know them very well for this sect...

Catherine_L_1C

https://i.stack.imgur.com/yo3Y0.png In a graph like this, subtract the energy of the reactants from the energy of the products. Depending on the sign of the difference in energy, you can tell if it's exothermic or endothermic. Negative means exothermic, and positive indicates an endothermic reactio...

Catherine_L_1C

Make sure you check your negative/positive signs and just make there's a 1.5 coefficient in front of the O₂ on the reactants side! That's what tripped me up.
Hope this helped :)

Catherine_L_1C

Hi! These are some rules that I remember/that I've seen: 1. Uncombined/free elements have an oxidation number of 0. 2. The sum of oxidation numbers in a neutral substance is 0. (Ex. in H 2 O, you know it's neutral so H must be +1 and O is -2) 3. For ions, the sum of oxidation numbers equals the char...

Catherine_L_1C

Hi,
Either way it shouldn't matter, because I believe Gibbs free energy is measured in J/mol, so as long as you end up solving for the value per 1 mol, you should be fine.

Hope this helped!

Catherine_L_1C

First law of thermodynamics? Don't talk about thermodynamics.

Catherine_L_1C

Hi,
Although it does seem a bit counterintuitive and confusing to name that process "fusion" when nothing is being fused together, the word originates from the Latin fundere, meaning "to melt." It's just a convention that chemists kept!

Catherine_L_1C

Hi, Enthalpy is considered a state function because its current value will only depend upon the final and initial values of heat in a reaction, but not the path or process that occurred for it to reach that value. In other words, theoretically a reaction could have the same enthalpy value whether it...

Catherine_L_1C

Since CO is a heteronuclear molecule you would use the z<8 diagram. Orient the O in a lower position however, since it is more electronegative. Following the diagram, the bonding sigma 2p orbital should be above the bonding pi 2p orbital. It should end up looking like this: http://www.meta-synthesis...

Catherine_L_1C

To my understanding, it's not the electron itself that is considered weaker, but an electron in an antibonding orbital will result in a weaker bond between two atoms because it has nodes in the bonding region between the nuclei, outside the bonding region. This pulls one nucleus away from the other ...

Catherine_L_1C

To my understanding, with heteronuclear molecules with 1 atom being z>8 and the other z<8, you should be using the z<8 diagram. Page 111 of the course reader references this!

Catherine_L_1C

It should be lavelle@chem.ucla.edu!

Catherine_L_1C

What did the orbital think of the chemistry homework?
He thought it was easy p_z!

Catherine_L_1C

The term ionic character is used when a large electronegativity difference exists between two atoms, in a way that one atom can possess most of the electrons and seem like an anion while the other resembles a cation. This can happen even if the bond is technically covalent, because in covalent bonds...

Catherine_L_1C

I interpreted it as the 5th group in the periodic table (V, Nb, Ta, Db) that happen to be transition metals, but if the solutions manual says that, then I guess we were meant to interpret it as the 5th group in the transition metals section. My answer for c would change then.

Catherine_L_1C

Hi Daniel, (a) The alkali metals are all the metals in Group 1A. They also all belong in the s-block, and will have 1 valence electron each. Therefore, depending on which shell the element is in, the configuration will be ns 1 . For example, sodium's will be 3s 1 . (b) Group 15 elements are in the p...

Catherine_L_1C

Hi Katie, To add onto what Shirley said, electrons in a resonance structure are considered to be "delocalized." Basically what that means is that they're not considered to be associated with any one atom or bond, and are in a "state of somewhere in between." This electron and cha...

Catherine_L_1C

Yeah! What'd you need help with?

Catherine_L_1C

This seems like such a great idea! Whenever we decide a date or time I'll be there; my email is catherinele98@g.ucla.edu. Hope to see everyone soon!

CHEMISTRY COMMUNITY

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Re: Simplified Nernst equation

Re: Catalyst [ENDORSED]

Re: Equivalent numbering - meaning?

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Re: Interpreting graphs [ENDORSED]

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Re: Understanding why enthalpy is a state function

Re: Molecular orbital theory of diatomic molecules

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Re: When making an M.O. diagram of 2 elements, where one has z<8 and the other one has z>/=8 how do you know which diagr

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