CHEMISTRY COMMUNITY

Myra_Zhan_2N

My TA said it will most likely be IUPAC naming in general, but if they want common name, the question will specifically ask for IUPAC and common names.

Myra_Zhan_2N

Just to clarify, tert- and sec- do not count in alphabetical order when naming, but iso- and neo- do right?

Myra_Zhan_2N

When you utilize E(cathode)-E(anode), take note that both are given as a reduction reaction value so be sure to check the negatives and positives.

Myra_Zhan_2N

You know you would have to use the pre-equilibrium approach when Step 1 is fast and Step 2 is slow. This is because the intermediate will be included in the rate law equation. That is not allowed so you would need to use substitution to replace the intermediate concentration.

Myra_Zhan_2N

The E value does not change when you multiply your half reactions. The only change an E value can have is a change in sign if the equation is flipped.

Myra_Zhan_2N

This is because delta E is an intensive property. Therefore, the constant is not multiplied by the delta E value, but the sign will change if the equation is flipped.

Myra_Zhan_2N

You can pick it up in Young Hall on the third floor (enter at the entrance to the right of the pillars). You just need to show your BruinCard to the guy at the front desk.

Myra_Zhan_2N

You would use ΔG^o=ΔH^o−TΔS^o after you find ΔH^o (rxn) and ΔS^o (rxn) values from the tables provided. Make sure your units match. You will need to convert ΔS^o to KJ for the final answer. That is the equation I am using. And I remembered to convert J to kJ. Still got the wrong answer. I also do n...

Myra_Zhan_2N

Can someone verify that the equation needed to solve #12 is the one we learned for calculating standard free energy change? I am getting caught up in the wording: "Calculate the standard Gibbs free energy". Should I be using a different equation (even though we're given standard change in...

Myra_Zhan_2N

Another important thing to remember is that q will always equal 0 in an adiabatic process in a closed system. q cannot be negative or positive because no heat is added or removed.

Myra_Zhan_2N

Does the negative sign in W=-P *ΔV represent the significance of energy used as a work of expansion?

Myra_Zhan_2N

According to the syllabus, there will just be practice quizzes in the course reader for our three quizzes.

Myra_Zhan_2N

My TA mentioned that when finding pH, it's just a general rule to keep it at two decimal places. So we would round off to the hundredth place.

Myra_Zhan_2N

If you're given Kb, it's the same case as Ka. There will only be an equilibrium constant if the base is not completely ionized in water. Therefore, Kb must be a weak base.

Myra_Zhan_2N

I believe that is an error. Nitrito is an anionic monodentate ligand.

Myra_Zhan_2N

A TA mentioned just to stick to the old names (bromo, iodo, etc.) when naming the anionic ligands. For the purpose of this class, it's not necessary to adapt to the new names.

Myra_Zhan_2N

We didn't really cover it in lecture, but it is part of the section explaining the properties of gases which is something we should know for the quiz.

Myra_Zhan_2N

Yes, the number of bonded atoms and number of unpaired electrons relative to the central atom is what determines the shape and bond angles of the molecule.

Myra_Zhan_2N

Greater electronegativity differences will have greater ionic character. Smaller electronegativity differences will have greater covalent character. The values of 1.5 and 2 just give a range as to see whether a bond is covalent or ionic based on electronegativity differences.

Myra_Zhan_2N

The central atom is generally the least electronegative atom. The electronegativity increases across a period but decreases down a group.

Myra_Zhan_2N

It is false because as the value of l increases, the electrons have a harder time penetrating to the nucleus.

Myra_Zhan_2N

Essentially, both can be used, but I personally prefer to use the latter one. When you have a question asking about the change from one energy level to another, I find it easier to plug the values in individually into the second equation. Afterwards, you can find the change in E by subtracting E (fi...

Myra_Zhan_2N

Madeline Fox 1J wrote:What is the conversion from Kev to J?

1 eV= 1.602 * 10^-19 Joules
1000 eV= 1 KeV

Hope this helps~

Myra_Zhan_2N

My TA said to keep the numbers as you work through the problem and find the final answer according to sigfigs at the end. He also mentioned a way to keep track of the final number of sigfigs is to underline the supposed final number of sigfigs each time as you work through each step of the problem.

Myra_Zhan_2N

I'm definitely interested in joining. Maybe a weekend afternoon and a couple weekday evenings?

CHEMISTRY COMMUNITY

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