CHEMISTRY COMMUNITY

Liam Giffin 2B

The 2-butanol indicates that the functional group is attached to the second carbon atom, but the second carbon atom is different from the secondary carbon atom. A secondary carbon atom is bonded to two other carbon atoms and a tertiary carbon atom is bonded to 3 other carbon atoms. The second carbon...

Liam Giffin 2B

It means that the carbon atom it is attached to is attached to two other carbons

Liam Giffin 2B

Well the rate constant is part of what determines the rate of the reaction. A larger rate constant corresponds to a faster reaction. If the energy barrier is lower then less energy is required for the reaction to occur, so the reaction will be faster and thus k must be larger.

Liam Giffin 2B

I don't really know much at all about this topic, but it is my understanding that the reaction cone is the range of angles at which a collision can occur in order for the reaction to occur. So the 2 Br atoms have to collide in a particular arrangement in order for the reaction to occur, the reaction...

Liam Giffin 2B

Larger atoms in the same group are more polarizable. For example Bromine is more polarizable than Fluorine, so Br- is a stronger nucleophile than F-. I'm pretty sure the trend isn't as definite as for some other things, but definitely the elements towards the bottom right of the period table are the...

Liam Giffin 2B

Technically they are both correct. The solution manual just chose to convert the given values from mmol/L to mol/L before doing calculations, which results in the answer in the solution manual. If you just leave those value in mmol/L then you will get a different answer, but both are technically cor...

Liam Giffin 2B

I would also do any problems after 79, because those mostly cover things that will be covered on the quiz. Definitely do 101 because it appears to me to be the only pre-equilibrium question in the book hw and that is something we need to know for the quiz.

Liam Giffin 2B

I'm not 100% certain but those things you listed all appear after page 73 in the course reader, so I don't think we will be assessed on anything from those sections on quiz 2.

Liam Giffin 2B

6 questions

Liam Giffin 2B

I think the answer to this is that it depends. Sometimes you will be given the temperature just so that you know that some given values are valid. For example, the standard enthalpies of formation are usually given at 25 degrees C, so often the only reason you are given the temp is so that you know ...

Liam Giffin 2B

So I'm not sure exactly where your issue is occurring, but I am not running into the same issue as you. When I use the formula ln(k)=\frac{nFE^{\circ}}{RT} the units cancel and I am left with a unitless K with the same value as listed in the book. In this case we use n as a pure number, so i...

Liam Giffin 2B

In the given equation both Ce4+ and Ce3+ are listed as aqueous which means that they are in the same solution. If both the oxidized and the reduced forms are listed as aqueous then that automatically means they are in the same solution as a part of the galvanic cell.

Liam Giffin 2B

This is mostly correct, because you want your cell potential to be positive, which will only occur if the reaction with the greater reduction potential occurs at the cathode and the reaction with the smaller reaction potential occurs at the anode. The only thing you said that I believe is incorrect ...

Liam Giffin 2B

For question 14.27 in the textbook I don't understand why we can't just add the potentials of reactions A and B (shown in solution manual answer) together. The problem and solution manual solution are shown below.

Liam Giffin 2B

On questions involving balancing are redox reaction in a basic or acidic solution will we always be told whether the reaction is occurring in an acidic or basic solution or is there some way that we should be able to figure that out ourselves?

Liam Giffin 2B

This is a little bit of a tough question to answer but I'll do my best and hopefully it will be somewhat helpful. 1) E^{\circ}cell=E^{\circ}(cathode) - E^{\circ}(anode) This is used to calculate the standard potential of a cell when we know the potentials for both the oxidation and t...

Liam Giffin 2B

Question 9.85 in the textbook says "Potassium nitrate dissolves readily in water, and its enthalpy of solution is +34.9 kJ* mol^{-1} ." Part C of the question then asks, "Is the entropy change of the system primarily a result of changes in the positional disorder or thermal disorder?&...

Liam Giffin 2B

Question 9.23 in the home work asks, "Which would you expect to have a higher molar entropy at T=0, single crystals of BF_{3} or of COF_{2} ? Why? The solution manual answer says " COF_{2} . COF_{2} and BF_{3} are both trigonal planar molecules, but it would be possible for the molecule to...

Liam Giffin 2B

In previous emails from Dr. Lavelle he said that our final exams from 14A would be available to be picked up in Young Hall 4006 this week. Is that still the case? At what times can we pick them up?

Liam Giffin 2B

Can anyone answer this?

Liam Giffin 2B

I am having trouble understanding problem 8.99 in the homework. I understand everything in the solution manual for the problem (problem and manual are pictured below) up until the point where they start finding the enthalpy of the reaction using tabulate enthalpies of formation. I understand where t...

Liam Giffin 2B

Never mind, I see that that conversion is derived on page 263 of the book.

Liam Giffin 2B

I was also having trouble with this problem. I do not understand where the 1Latm=101.325J conversion comes from. Where does that conversion come from?

Liam Giffin 2B

I have a somewhat similar question. It appears in the solutions manual and previous finals solutions that in calculations involving a kp^a of kp_b that the sig figs of the kpa or kpb are ignored in the solution. Is this true?

Liam Giffin 2B

I also had trouble with this problem. In part B the solutions manual finds the concentrations of CH3COOH and CH3CO2- after neutralization, which makes sense to me. Then it sets up an ICE box to solve for the hydronium ion concentration. This works, but I also got the same answer when I plugged in th...

Liam Giffin 2B

I have posted the full question and answer below. I also don't understand how they are able to just "push the reaction" to the left. How are they able to do that and what is the procedure for going about that?

Liam Giffin 2B

Problem #11 says, "A 0.10 mol sample of pure ozone, O 3 , is placed in a sealed 1.0 L container and the reaction 2O 3 (g) \rightleftharpoons 3O 2 (g) is allowed to reach equilibrium. A 0.50 mol sample of pure ozone is placed in a second 1.0 L container at the same temperature and allowed to rea...

Liam Giffin 2B

For part a of 33 the lewis structure I got (pictured below) would suggest that it is a bidentate ligand. Why is that incorrect?

Liam Giffin 2B

Electrons in an anti-bonding molecular orbital do not participate in bond formation, so electrons in an anti-bonding MO would correspond to lone pairs on an atom. However electrons in bonding orbitals are the electrons that are used to form sigma and pi bonds. Electrons fill the bonding orbitals fir...

Liam Giffin 2B

Question 3.103 form the book is shown in the picture below, along with the answer for part C of the question. I do not understand how you arrive at the solution manual answer for part C (pictured below) from what you are given in the book. It says that 2 protons are added and then the book answer ad...

Liam Giffin 2B

For question 3.57 in the homework the book asks you to "write the Lewis structure, including typical contributions to the resonance structure (where appropriate, allow for the possibility of octet expansion, including double bonds in different positions), for; (b) a hydrogen sulfite ion. I star...

Liam Giffin 2B

I'm having trouble with question 2.93 in the chapter 2 homework. I have attached the question and the solution manual answer. The way I see it, Na has the larger atomic radius, so it must be represented initially by circle B and Cl has the smaller atomic radius so it must correspond to circle A. Thi...

Liam Giffin 2B

I'm confused, because in the balanced equation you, Alicia, posted, the first product you have is 2 N_{2} , but in the unbalanced equation you are given the first product is NO (g), not just N (g) or N_{2} (g). Problem 9 of the fundamentals self test in the workbook is basically the same and I was h...

Liam Giffin 2B

I have an add on question. For question 1.15 in the homework it just gives us a wavelength of 102.6 nm and asks us to find the final and initial energy levels n that lead to this spectral line. I don't see any way to do this without using the Rydberg equation v=R(\frac{1}{n^{2}}-\frac{1}{n^{2}}&...

CHEMISTRY COMMUNITY

Search found 34 matches

Re: Alcohol 2-methyl-2-butanol [ENDORSED]

Re: Alcohol

Re: Ratio of Rate Constants (Energy Barriers)

Re: Reaction Cone

Re: Polarization and nucleophile strength

Re: 15.19 Homework

Re: Book problems for quiz 2?

Re: Quiz 2

Re: Quiz 2

Re: Sig Figs

Re: Midterm 2014 Question 8

Re: Textbook Question 14.13b

Re: Determine Cathode and Anode

14.27

Acidic vs. Basic Solution

Re: Formulas

HW #9.85

Question 9.23

14A Final Exams

Re: HW Problem 8.99

HW Problem 8.99

Re: Problem 8.3

Re: Problem 8.3

Re: Sig Figs in pH

Re: Chapter 13 #35

Re: HW 11.67

11.11 [ENDORSED]

Re: Homework 17.33

Re: Molecular orbital theory question

3.103

Question 3.57 B

Chapter 2, Homework Problem 2.93

Re: Quiz 1 prep. #8-Limiting reagent [ENDORSED]

Re: Rydberg Formula [ENDORSED]