Search found 26 matches
- Sun Mar 19, 2017 7:02 pm
- Forum: Second Order Reactions
- Topic: Pre- equilibrium approach [ENDORSED]
- Replies: 3
- Views: 927
Re: Pre- equilibrium approach [ENDORSED]
Usually when there's an intermediate involved, you have to use the pre equilibrium approach.
- Sun Mar 12, 2017 10:43 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Winter 2016 final 4B
- Replies: 4
- Views: 1032
Re: Winter 2016 final 4B
O is a catalyst so it's not actually involved in the reaction
- Fri Mar 03, 2017 5:08 pm
- Forum: *Alkanes
- Topic: Naming Organic Compounds (substituents)
- Replies: 1
- Views: 601
Re: Naming Organic Compounds (substituents)
usually when naming organic compounds, you want to put the substituent as close to 1 as possible when naming. that's probably why
- Mon Feb 27, 2017 1:24 am
- Forum: Arrhenius Equation, Activation Energies, Catalysts
- Topic: k, temperature, and activation energy
- Replies: 2
- Views: 614
Re: k, temperature, and activation energy
At higher temperatures, molecules are moving a lot faster because there is more energy in the environment (temperature is the measure of heat, which is energy in the environment). Because of this, they are more likely to be able to collide at the required energy level
- Mon Feb 20, 2017 9:30 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Diamond and graphite
- Replies: 8
- Views: 3552
Re: Diamond and graphite
Calculating by kinetics (by k and stuff) provides an answer that is mostly stable for diamond, but the thermodynamic equations (gibbs free energy) show that it is unstable.
- Mon Feb 20, 2017 9:29 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: # of elementary steps?
- Replies: 2
- Views: 660
Re: # of elementary steps?
They should give you the steps, otherwise any number of steps could technically occur.
- Fri Feb 10, 2017 4:45 pm
- Forum: Third Law of Thermodynamics (For a Unique Ground State (W=1): S -> 0 as T -> 0) and Calculations Using Boltzmann Equation for Entropy
- Topic: Question 3 from Quiz 1
- Replies: 1
- Views: 521
Re: Question 3 from Quiz 1
They are not perfect crystals, which is the problem. Thus they cannot be exactly S=0. You have to figure out the entropy using the equation S = K ln W W is the number of different configurations that a molecule can have. Since SF6 has only one configuration, but SF5CL can have many different configu...
- Sat Feb 04, 2017 11:36 am
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Calculating Heat [ENDORSED]
- Replies: 2
- Views: 665
Re: Calculating Heat [ENDORSED]
It sounds like it's referring to calculating the energy it takes to convert between states of matter.
- Mon Jan 30, 2017 11:55 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Molecules and Disorder
- Replies: 1
- Views: 533
Re: Molecules and Disorder
Polarity should not have anything to do with disorder, because it is less to do with energy and more to do with attraction
- Tue Jan 24, 2017 12:57 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Ch 8 Exercise 77
- Replies: 3
- Views: 931
Re: Ch 8 Exercise 77
According to an online source ( http://web.chem.ucla.edu/~harding/IGOC/K/kekule_structure.html ) it is a Lewis structure in which bonded electron pairs in covalent bonds are shown as lines and avoids showing lone pairs. Resonance just makes the kekule structure show two different versions of benzene...
- Tue Jan 24, 2017 12:50 pm
- Forum: Calculating Work of Expansion
- Topic: Combustion Reaction - Writing and Balancing
- Replies: 2
- Views: 677
Re: Combustion Reaction - Writing and Balancing
H2O is normally a liquid. Especially since the combustion reaction appears to be just two liquids reacting with each other, which means that most likely they are not heating up enough to react. O2 liquid is usually found in only extremely cold temperatures. You can double the equation if needed, but...
- Thu Jan 12, 2017 2:10 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: standard reaction enthalpy
- Replies: 2
- Views: 482
Re: standard reaction enthalpy
I am pretty sure we will be given standard reaction enthalpies if it is needed. Otherwise, it'll be something we need to figure out from the problem provided, so it wouldn't be provided at that point.
- Sat Dec 03, 2016 7:41 pm
- Forum: *Titrations & Titration Calculations
- Topic: 2007 Final Q5
- Replies: 2
- Views: 1032
Re: 2007 Final Q5
Don't we get a list of weak and strong acids? Also, you can derive the formula from the name. Methyl = CH3, Amine = NH2
- Sat Dec 03, 2016 7:39 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Ice Table Variables
- Replies: 1
- Views: 547
Re: Ice Table Variables
Actually, it's when x is less than 5% of the initial amount, after you calculate it. Not Ka.
- Mon Nov 28, 2016 1:14 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Fall 2014 Final Exam #6A
- Replies: 1
- Views: 546
Re: Fall 2014 Final Exam #6A
They basically just simplified the problem and substituted in the Kc value. The Equation is merely a simplified way of writing out the complicated fractions.
- Sun Nov 27, 2016 4:55 pm
- Forum: Bronsted Acids & Bases
- Topic: Strong and Weak Acids
- Replies: 1
- Views: 533
Re: Strong and Weak Acids
No, it is not considered to be in equilibrium. The rate of change for the forward reaction must equal the rate of change for the opposite reaction in order to be considered at equilibrium.
- Sun Nov 20, 2016 11:48 pm
- Forum: Ideal Gases
- Topic: Partial Pressure
- Replies: 4
- Views: 1008
Re: Partial Pressure
I believe sometimes when a reaction occurs, the changes in the amount of reactants and products can sometimes balance out to make an overall no change in pressure.
- Sun Nov 06, 2016 10:08 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Transition Metal Cations and H2O
- Replies: 1
- Views: 690
Re: Transition Metal Cations and H2O
I read somewhere that it's because despite H2O having two pairs, the H2O prefers not to share the second pair of electrons, so technically that would make the H2O provide the same amount of electrons as the other elements. Don't quote me exactly on this however. I have also read that a ligand's stre...
- Thu Oct 27, 2016 7:35 pm
- Forum: Dipole Moments
- Topic: Charge distribution in molecules
- Replies: 1
- Views: 536
Re: Charge distribution in molecules
Which parts specifically do you need explaining in this section? In short, this section basically talks about how each element has its own level of strength when pulling in electrons. Just like how each person can lift a certain weight, each element has its own pull on electrons. Because of this, el...
- Fri Oct 21, 2016 4:56 pm
- Forum: Electronegativity
- Topic: Dipole moment
- Replies: 2
- Views: 839
Re: Dipole moment
There are different degrees of polarity, and this arises mostly due to the electronegativity of elements (how strong they pull on the electrons). Oxygen is known for having high electronegativity, which means it pulls it very strongly while H is known for being weaker, which is also why water is a p...
- Fri Oct 21, 2016 4:47 pm
- Forum: Lewis Structures
- Topic: Lewis structure of H3PO4
- Replies: 1
- Views: 737
Re: Lewis structure of H3PO4
It's probably more accurate to draw it the second way, just because that's how the molecule works normally, and the first method is more for two molecular ions rather than a single element and a molecule (eg (nh3)3PO4)
- Mon Oct 10, 2016 1:33 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3864994
Re: Post All Chemistry Jokes Here
Gold walks into a bar. The bartender shouts "Ay you! Get out of here!"
- Thu Oct 06, 2016 3:02 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterm Date
- Replies: 3
- Views: 829
Re: Midterm Date
Thank you!
- Wed Oct 05, 2016 3:35 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterm Date
- Replies: 3
- Views: 829
Midterm Date
Is the midterm on Nov. 2nd at 4PM for those taking LS30A? just wanted to make sure. Thanks in advance!
- Tue Sep 27, 2016 12:04 am
- Forum: Properties of Light
- Topic: Photons
- Replies: 4
- Views: 888
Re: Photons
I believe that it is because the higher the frequency the stronger it is. For example a radio wave, which has a low frequency rate, is weaker than a gamma ray, which has a high frequency (due to shorter wavelength).
- Mon Sep 26, 2016 11:59 pm
- Forum: Student Social/Study Group
- Topic: Rieber Hall 14A Study Group (Fall 2016)
- Replies: 49
- Views: 10221
Re: Rieber Hall 14A Study Group (Fall 2016)
I'm from Rieber Vista, and this sounds pretty cool. Where would the meeting place be?