Search found 10 matches

by April Z 1K
Sun Mar 19, 2017 1:42 am
Forum: Administrative Questions and Class Announcements
Topic: Saying Thank You to Dr. Lavelle
Replies: 200
Views: 45716

Re: Saying Thank You to Dr. Lavelle

Dear Dr. Lavelle,
Thank you for all you've done for the class, from the time you've invested into making the solid lectures, to organizing all the resources available (bruincast, review sessions, etc). Your attentiveness and effort is appreciated, and It's been a tough but memorable quarter.
by April Z 1K
Sat Mar 18, 2017 6:52 pm
Forum: *Cycloalkenes
Topic: Question about 1,6-dichlorocyclohexene
Replies: 1
Views: 495

Re: Question about 1,6-dichlorocyclohexene

In this case, I think it's because the 1 before cyclohexene is unnecessary (maybe not the best word to use). There are no functional groups like alcohol, so the double bond should automatically be assumed to be between C 1 and 2, and doesn't need to be specified. Though, I don't think points would b...
by April Z 1K
Sun Mar 12, 2017 10:05 pm
Forum: *Identifying Primary, Secondary, Tertiary, Quaternary Carbons, Hydrogens, Nitrogens
Topic: Picture of difference between sec/iso and neo/tert?
Replies: 3
Views: 704

Re: Picture of difference between sec/iso and neo/tert?

Building on that, the "Y" (iso-)/ "triple branched" (neo-) structures occur at the end of the substituent. "Sec" and "Tert" refer to how many Carbons in the substituent are connected to the C between it and the rest of the molecule. The end of this video might...
by April Z 1K
Sun Mar 05, 2017 6:03 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7337
Views: 825509

Re: Post All Chemistry Jokes Here

Q: What did the Electrophile say to Benzene?
A: I want some of that sweet pi.
by April Z 1K
Sun Feb 26, 2017 12:39 pm
Forum: Method of Initial Rates (To Determine n and k)
Topic: Rate Order
Replies: 5
Views: 679

Re: Rate Order

I think it can be solved using experimental data and ratios (method we're using now), except the exponent (n) would be a fraction?
by April Z 1K
Sun Feb 19, 2017 3:05 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7337
Views: 825509

Re: Post All Chemistry Jokes Here

Q: Why do chemistry students do well when working with ammonia?
A: Because it's pretty basic stuff.
by April Z 1K
Sun Feb 12, 2017 5:36 pm
Forum: Calculating Standard Reaction Entropies (e.g. , Using Standard Molar Entropies)
Topic: Practice Midterm Winter 2013: Q5B
Replies: 3
Views: 358

Re: Practice Midterm Winter 2013: Q5B

Another way you can look at it is the amount of "disorder," I think. CF bonds are more polar than CH bonds, so having 4 CF bonds vs. 2 makes for more "disorder" and thus larger molar entropy.
by April Z 1K
Sun Jan 29, 2017 7:59 pm
Forum: Thermodynamic Systems (Open, Closed, Isolated)
Topic: 9.35
Replies: 1
Views: 262

Re: 9.35

Not sure about this, but I think entropy of system A > entropy of system C because monatomic gases result in more "disorder" in the system (have more possible "states"). Hope this helps.
by April Z 1K
Sun Jan 22, 2017 11:39 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Standard Enthalpy of Formation Course Reader example
Replies: 1
Views: 241

Re: Standard Enthalpy of Formation Course Reader example

The standard reaction enthalpy is divided by 2 because the example is looking for the formation of 1 mole of CH3CH2OH, whereas the rxn enthalpy gives the kJ amount for 2 moles of CH3CH2OH. Hope this helps.
by April Z 1K
Sun Jan 15, 2017 10:32 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Method 2: Bond Enthalpies [ENDORSED]
Replies: 2
Views: 303

Re: Method 2: Bond Enthalpies [ENDORSED]

When using bond enthalpies, it's just summation, not [summation of products] - [summation of reactants]. As stated in the example, double bond C=C and single bond H-Br is broken (+978kJ, requires energy). Single bonds C-C, C-H, and C-Br are formed (-1036kJ, releases energy). Adding the two together,...

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