Search found 10 matches

by AlyssaD_2K
Mon Mar 13, 2017 10:47 pm
Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
Topic: Example on Page 17 (Organic Textbook)
Replies: 1
Views: 324

Re: Example on Page 17 (Organic Textbook)

I think that the E and Z are referring to the methyl groups and which side of the double bond they are on in relation to each other. For E, the methyl groups are on the opposite side, and for Z, the methyl groups are on the same side.
by AlyssaD_2K
Mon Mar 06, 2017 10:29 pm
Forum: *Organic Reaction Mechanisms in General
Topic: Reaction Profiles
Replies: 2
Views: 436

Re: Reaction Profiles

In addition, I would add that the slow step in the reaction is the elementary step with the highest activation energy (you can see this from the Arrhenius equation) and therefore that transition state would have the highest energy.
by AlyssaD_2K
Thu Mar 02, 2017 10:28 pm
Forum: *Alkanes
Topic: Drawing Organic Molecules
Replies: 1
Views: 326

Re: Drawing Organic Molecules

It just means that those atoms are grouped together. So in your example, CH2 is grouped together, which makes sense when you draw out the entire hydrocarbon chain. I think that when there are substituents, you have to write it in the way that Lavelle taught us on Wednesday which clearly defines what...
by AlyssaD_2K
Fri Feb 24, 2017 6:18 pm
Forum: *Organic Reaction Mechanisms in General
Topic: Determining Where Hydrogen Bonds
Replies: 5
Views: 766

Re: Determining Where Hydrogen Bonds

The double bond between the carbon atoms contain a lot of electrons, giving that area a more negative charge. That's why the hydrogen in the HBr molecule is attracted to it, because the H has a partial positive charge and Br has a partial negative charge due to its larger electronegativity. When the...
by AlyssaD_2K
Mon Feb 20, 2017 4:46 pm
Forum: General Rate Laws
Topic: Elementary Rate Laws
Replies: 1
Views: 338

Re: Elementary Rate Laws

I think it's because the overall reaction may have multiple elementary steps, but the elementary reaction itself is the simplest. Because of this, we can use the coefficients for the elementary reaction in its rate law. Since we do not know the mechanism behind the overall reaction, we can't do this...
by AlyssaD_2K
Sat Feb 11, 2017 8:52 pm
Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
Topic: 14.9 and using G=-nFE
Replies: 3
Views: 639

Re: 14.9 and using G=-nFE

Both of those constants are the same, just one is a little more specific. I wouldn't worry about which one you use, just use the one given when you take the test.
by AlyssaD_2K
Sat Feb 04, 2017 9:11 pm
Forum: Balancing Redox Reactions
Topic: Calculating standard reduction potential
Replies: 1
Views: 218

Re: Calculating standard reduction potential

In that example, you don't need to switch the sign because the total reaction includes the forward half reaction of the cathode, so we want that value. However, we want the reverse half reaction of the anode, so that's why you need to change the sign of that one.
by AlyssaD_2K
Sat Jan 28, 2017 6:40 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Mean bond Enthalpies
Replies: 1
Views: 314

Re: Mean bond Enthalpies

I'm pretty sure that any kind of information like that will be provided.
by AlyssaD_2K
Wed Jan 18, 2017 11:19 pm
Forum: Concepts & Calculations Using First Law of Thermodynamics
Topic: Another "work" definition? [ENDORSED]
Replies: 1
Views: 363

Another "work" definition? [ENDORSED]

In the textbook and in HW problem 8.11 the equation w=-nRT*ln(V2/V1) was used.
I was confused about how this was derived and if this is a definition we will be using in class/may be tested on.
Thank you!
by AlyssaD_2K
Sat Jan 14, 2017 9:18 pm
Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
Topic: Extensive Property vs. Intensive Property
Replies: 2
Views: 378

Re: Extensive Property vs. Intensive Property

From my understanding, I'm pretty sure that the heat capacity is always an extensive property. Dividing by the amount (like in the example in the course reader) gives an answer that is "per degree Celsius" because we want the units to be kJ/Celsius (since heat capacity is the heat required...

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