Search found 10 matches

by Amber Duong 1B
Sat Mar 18, 2017 9:10 pm
Forum: *Organic Reaction Mechanisms in General
Topic: Quiz 2
Replies: 3
Views: 485

Re: Quiz 2

The rate limiting step was the first step because its reaction constant was less than the second step, meaning that it was slower.
by Amber Duong 1B
Sat Mar 11, 2017 5:39 pm
Forum: *Electrophiles
Topic: Nucleophile vs Electrophile
Replies: 5
Views: 816

Re: Nucleophile vs Electrophile

Generally, a nucleophile is a molecule that has lone pairs to donate and can be neutral or negatively charged (more electronegative). On the other hand, electrophiles want to have a complete set of 8 valence electrons and are usually neutral or positively charged (less electronegative). The surround...
by Amber Duong 1B
Sat Mar 04, 2017 9:54 pm
Forum: Administrative Questions and Class Announcements
Topic: 4.1
Replies: 3
Views: 210

Re: 4.1

The Grignard reactants are just compounds that generate very reactive nucleophiles. This is because they cause the carbon atom to become attached to a metal ion, which causes the carbon to attract extra electrons from the metal atom and become a nucleophile.
by Amber Duong 1B
Sun Feb 26, 2017 3:10 pm
Forum: Kinetics vs. Thermodynamics Controlling a Reaction
Topic: Quiz 2 #9 and #10
Replies: 3
Views: 328

Re: Quiz 2 #9 and #10

For #10, I plugged in the concentrations into the 2nd order integrated rate law.
1/0.5= 1/1 + kt
1/0.25=1/0.5 +kt

These equations become...
1=kt and 2=kt which become...
1/k=t and 2/k=t.

Since k is the same for both rate laws, the t(time) will be different, so the answer is FALSE.
by Amber Duong 1B
Wed Feb 15, 2017 4:44 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Determine Cathode and Anode
Replies: 2
Views: 257

Re: Determine Cathode and Anode

The strongest oxidizing agent is the one with the most positive reduction potential. Also this will be the electrode that is reduced in the cathode. On the other hand, the weakest oxidizing agent or strongest reducing agent is the one with the most negative reduction potential, and it will be oxidiz...
by Amber Duong 1B
Tue Feb 07, 2017 10:14 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: memory trick [ENDORSED]
Replies: 3
Views: 511

Re: memory trick [ENDORSED]

Another trick for memorizing oxidation and reduction reactions is "LEO says GER". LEO- Losing Electrons Oxidation, GER- Gaining Electrons Reduction. Hope it helps!
by Amber Duong 1B
Wed Feb 01, 2017 6:27 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Bond Enthalpies
Replies: 2
Views: 282

Re: Bond Enthalpies

To calculate enthalpy change of a reaction using bond enthalpies, you can add up either the bond enthalpies of the bonds broken and bonds made OR the bond enthalpies of the reactants and the products. It equates to the same enthalpy change.
by Amber Duong 1B
Fri Jan 27, 2017 10:43 am
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: Change in the entropy of the universe
Replies: 1
Views: 188

Re: Change in the entropy of the universe

If temperature is constant for the system and its surroundings, the entropy for both are equal and opposite values. For example, the system losing heat is a negative entropy value while the surroundings gain that heat and have the opposite, positive entropy value. Thus, total entropy change of the u...
by Amber Duong 1B
Sun Jan 22, 2017 9:37 pm
Forum: Thermodynamic Systems (Open, Closed, Isolated)
Topic: Understanding experiments with beakers
Replies: 1
Views: 168

Re: Understanding experiments with beakers

An open system can exchange energy or matter with its surroundings. A closed system can exchange only energy with its surroundings while an isolated system can exchange nothing with its surroundings. One example of a open system would be to add gas in a car, which physically adds matter into the sys...
by Amber Duong 1B
Wed Jan 11, 2017 9:06 pm
Forum: Phase Changes & Related Calculations
Topic: Steam Severe Burns Question
Replies: 3
Views: 277

Re: Steam Severe Burns Question

Lets assume the temperature of skin is 30 degrees Celsius. When steam at 100 degrees Celsius hits the skin, it immediately condenses to water at 30 degrees Celsius. Thus, first, the steam undergoes a reaction to change into water at 100 degrees Celsius, which releases 41 kJ. Then the water has to co...

Go to advanced search