Search found 12 matches

by AshleyAguilar_1F
Thu Mar 16, 2017 9:32 pm
Forum: *Alkanes and Substituted Alkanes (Staggered, Eclipsed, Gauche, Anti, Newman Projections)
Topic: self test 3.3A
Replies: 1
Views: 289

self test 3.3A

why would there be more molecules in the gauche conformation at higher temperatures?
by AshleyAguilar_1F
Tue Mar 07, 2017 6:03 pm
Forum: *Organic Reaction Mechanisms in General
Topic: 4.26 ochem textbook
Replies: 3
Views: 560

4.26 ochem textbook

In this question it asks to complete the reaction mechanism, and in the answer the Iodine is on the left carbon and the Hydrogen is on the right carbon, but can it be the other way around? (hydrogen on left carbon, iodine on right carbon)
by AshleyAguilar_1F
Tue Feb 28, 2017 7:49 pm
Forum: *Electrophiles
Topic: 4.11, 4.13
Replies: 2
Views: 450

4.11, 4.13

At this point are we supposed to be able to give an example of an Organolithium compound? or an alkyl Grignard reactant? and give examples of alkenes and alkynes? It asks these kinds of questions throughout the section but there isn't very much information about them in the text
by AshleyAguilar_1F
Tue Feb 14, 2017 7:25 pm
Forum: Gibbs Free Energy Concepts and Calculations
Topic: 9.55
Replies: 1
Views: 292

9.55

It asks to write balanced equations before calculating enthalpy, entropy, and gibbs free energy. Does the equation need to have the smallest possible molar ratios? I balanced the equation as 3H2 (g) + N2 (g) --> 2NH3 (g) and I got a different answer for entropy than the solutions manual
by AshleyAguilar_1F
Mon Feb 13, 2017 6:38 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: 14.11 d)
Replies: 2
Views: 342

14.11 d)

So for the right side of the cell diagram the half-reaction should be O2 (g) + 2H2O (l) + 4e- --> 4OH - (aq) . **originally just O2 (g) --> OH- (aq)** I don't understand why the water molecules are on the reactants side if the first step to balancing the equation is to balance the oxygen molecules (...
by AshleyAguilar_1F
Thu Feb 09, 2017 5:45 pm
Forum: Balancing Redox Reactions
Topic: 14.3
Replies: 2
Views: 321

Re: 14.3

thanks!
by AshleyAguilar_1F
Thu Feb 09, 2017 1:47 pm
Forum: Balancing Redox Reactions
Topic: 14.3
Replies: 2
Views: 321

14.3

the skeletal equation is: Cl2 (g) + S2O3 2- (aq) --> Cl- (aq) + SO4 2- Chorine gas is gaining just 1 electron... okay so in the solutions manual the reduction half-reaction is Cl2 (g) + 2e- --> 2Cl- (aq) and I do not understand why we add 2 electrons; that would make the left side have a charge of 2...
by AshleyAguilar_1F
Mon Jan 30, 2017 1:21 pm
Forum: Concepts & Calculations Using Second Law of Thermodynamics
Topic: 9.7
Replies: 1
Views: 249

9.7

"Assuming that the heat capacity of a ideal gas is independent of temperature, calculate the entropy change associated with raising the temp 1.00 mol of ideal gas atoms.... "

How do we know that this is a monatomic gas?
by AshleyAguilar_1F
Sun Jan 29, 2017 4:21 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Question 8.45
Replies: 1
Views: 285

Question 8.45

The units given for delta H of the reaction is given as 358.8 kJ (not per mole), but the solutions manual gives the enthalpy in kJ/mol and so delta H is multiplied by the 1.25 mols of Sulfur in order to cancel the units. Why did they just change the units? Anyways I thought kJ/mol was used for phase...
by AshleyAguilar_1F
Sun Jan 22, 2017 6:49 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: HW 8.67
Replies: 3
Views: 538

Re: HW 8.67

Graphite is solid, but we need it to be in the form of a gas. Sublimation is Hvapor - Hsolid, and the problem said the sublimation of carbon is +717 kJ*mol, so 717- 0 (enthalpy of carbon in it's most stable form graphite is 0) = +717kJ*mol^-1.
by AshleyAguilar_1F
Fri Jan 20, 2017 2:19 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: HW 8.67 b) [ENDORSED]
Replies: 1
Views: 271

HW 8.67 b) [ENDORSED]

I thought that the formation of methanol was CO + 2H2. While it makes sense to me why it is actually set up C (gr) + 2H2 (g) + 1/2O2, I don't understand how we are supposed to know that this is the way it's done for this particular problem. CO is bonded by a triple bond, which is a mean bond enthalp...
by AshleyAguilar_1F
Mon Jan 16, 2017 11:16 pm
Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
Topic: Problem 8.57 (Hess's Law)
Replies: 2
Views: 409

Problem 8.57 (Hess's Law)

When writing out the balanced equations for the reaction given do we need to use the most simplified (in terms of the moles) equation? For example, for the combustion of H2 I have it written as 2H2 + O2 --> 2H2O but the solutions manual has it more simplified (H2 + 1/2O2 --> H2O), and so the answers...

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