Search found 12 matches
- Mon Mar 13, 2017 9:06 pm
- Forum: General Rate Laws
- Topic: coefficients
- Replies: 2
- Views: 544
Re: coefficients
Coefficients are only placed in the rate law when you are given the rate limiting step in a reaction mechanism. If don't have such information, you cannot assume that the overall reaction determines the rate law. To determine the rate law in that scenario, you must calculate it using different exper...
- Mon Mar 06, 2017 6:02 pm
- Forum: *Cycloalkanes
- Topic: Confusiong of Naming Cycloalkanes
- Replies: 2
- Views: 557
Re: Confusiong of Naming Cycloalkanes
You can see that Cyclohexane only has one substituent. Since cyclohexane is a ring, any carbon in the ring could be your starting carbon. IUPAC naming likes to have the smallest numbers in their names, so you want to make that carbon attached to your substituent your first carbon in the Cyclohexane....
- Mon Feb 27, 2017 2:32 pm
- Forum: General Rate Laws
- Topic: Pre-equilibrium Approach
- Replies: 2
- Views: 546
Re: Pre-equilibrium Approach
How would you go about doing the problem though? How can there be any equilibrium constant if all the products made in the slow reactions become reactants right away in the fast reaction?
- Mon Feb 27, 2017 12:18 pm
- Forum: General Rate Laws
- Topic: Pre-equilibrium Approach
- Replies: 2
- Views: 546
Pre-equilibrium Approach
Could you use the pre-equilibrium approach when the first step is slow or can you only use that approach when the second step is slow?
- Sat Feb 25, 2017 2:59 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3893256
Re: Post All Chemistry Jokes Here
A small piece of sodium that lived in a test tube fell in love with a Bunsen burner. "Oh Bunsen, my flame," the sodium pined. "I melt whenever I see you," The Bunsen burner replied, "It's just a phase you're going through."
- Sat Feb 18, 2017 10:46 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3893256
Re: Post All Chemistry Jokes Here
If the Silver Surfer and Iron Man team up, they’d be alloys.
- Tue Feb 14, 2017 6:21 pm
- Forum: Student Social/Study Group
- Topic: 14C discussion Switch
- Replies: 1
- Views: 530
14C discussion Switch
Hello,
I am currently enrolled in discussion 1L in Hardinger's 14C class. Would anyone want to switch with me?
Thank you.
I am currently enrolled in discussion 1L in Hardinger's 14C class. Would anyone want to switch with me?
Thank you.
- Thu Feb 09, 2017 2:32 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Homework 14.11
- Replies: 1
- Views: 484
Re: Homework 14.11
The solution Manual used the formula Ecell = Cathode - anode. However, if you switched the sign for the anode and then added it to the cathode value then you would still get the same answer.
- Tue Jan 31, 2017 11:33 am
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: Definition of Isothermal Reactions
- Replies: 2
- Views: 921
Re: Definition of Isothermal Reactions
The delta T of the system would be zero if you are calculating the entire process: 290 to 295 to 290. Delta T = 290-290. If no work is done by the system during the heating and cooling, then Delta U = 0.
- Thu Jan 26, 2017 11:59 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Entropy
- Replies: 7
- Views: 1250
Entropy
What effect does the being reversible vs irreversible have on entropy? How would you calculate both?
- Fri Jan 20, 2017 9:17 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: Degeneracy [ENDORSED]
- Replies: 3
- Views: 917
Re: Degeneracy [ENDORSED]
I do not believe that an O2 molecule would have a w=0. If you have one molecule of O2 at T=0 K, much like the problem in the course reader, there is only one possible position for such atom: O-O. 1 possible position and 1 atom would lead to w=1. However, with a degeneracy of 1, entropy would be 0. S...
- Thu Jan 12, 2017 4:12 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpies to Calculate deltaH_RXN
- Replies: 1
- Views: 407
Re: Bond Enthalpies to Calculate deltaH_RXN
On the course reader, you would have to compare the product bonds with the reactant bonds, finding out which ones stay intact and which ones are broken and then formed again. In that problem, one could see the double bond is broken and then formed as a single bond. Since we cannot calculate the ener...