viewtopic.php?f=140&t=20850&p=59021&hilit=cell+diagram&sid=62cad8228751744d5735abc415246b2e#p59021
I was stuck on this too, but its due to counter ions that's coming back into half cell with Ag+.
Search found 31 matches
- Sun Mar 19, 2017 9:00 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Midterm 2016 Q3C
- Replies: 2
- Views: 651
- Sun Mar 19, 2017 3:53 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Winter 2016 Q3C (p.207)
- Replies: 3
- Views: 925
Re: Winter 2016 Q3C (p.207)
viewtopic.php?f=140&t=20850&p=59021&hilit=cell+diagram&sid=62cad8228751744d5735abc415246b2e#p59021
nevermind I found it.
Hope this helps you too Huongly!
nevermind I found it.
Hope this helps you too Huongly!
- Sun Mar 19, 2017 3:51 am
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Winter 2016 Q3C (p.207)
- Replies: 3
- Views: 925
Re: Winter 2016 Q3C (p.207)
First the conventional way of writing the cell diagram is Reactant, Product, Reactant, Product etc. The reason AgBr(s) is in the diagram is because it is solid and Ag+ has been oxidized and that is why it is to included in the diagram. It is actually supposed to be the whole solid rather than the d...
- Thu Mar 16, 2017 6:19 pm
- Forum: *Alkanes and Substituted Alkanes (Staggered, Eclipsed, Gauche, Anti, Newman Projections)
- Topic: staggered vs eclipsed stability
- Replies: 3
- Views: 890
Re: staggered vs eclipsed stability
180 degrees - anti staggered would be the lowest energy conformation.
- Fri Mar 10, 2017 2:36 pm
- Forum: *Alkanes
- Topic: Iso / Neo when to use
- Replies: 3
- Views: 832
Re: Iso / Neo when to use
iso on a substituent is used when it is not attached in a linear structure.
- Fri Mar 03, 2017 11:25 pm
- Forum: *Alkanes
- Topic: About the Weekly Online Discussion Points...
- Replies: 3
- Views: 881
Re: About the Weekly Online Discussion Points...
Do we then get extra points for posting more than one each week?
I thought I heard somewhere we get like 2% extra credit??
Can anybody confirm this?
Thank you
I thought I heard somewhere we get like 2% extra credit??
Can anybody confirm this?
Thank you
- Wed Feb 22, 2017 1:39 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: assuming order from units of k
- Replies: 1
- Views: 472
Re: assuming order from units of k
Yes you can figure out the order of reaction by looking at the units of k. Because the unit of rate is M/s, if you plug the unit of rate in 0 order, 1st order, and 2nd order rate law, you will be able to get the unit of k for different orders. For example rate=k[A]^0 for 0 order. Since you know that...
- Wed Feb 22, 2017 1:25 pm
- Forum: General Rate Laws
- Topic: Units for Reaction Rate and the Rate Constant
- Replies: 3
- Views: 1137
Re: Units for Reaction Rate and the Rate Constant
The units of rate constant is varies for the different depending on the order of reaction.
- Tue Feb 21, 2017 10:42 pm
- Forum: Second Order Reactions
- Topic: 15.35
- Replies: 1
- Views: 562
Re: 15.35
For second order, -d[A]/dt = k[A]^2 . Integration of both sides results in an equation 1/[A] = kt + 1/[A]0. Hence, in order to find out for the half life, we use this equation when it is in second order.
- Tue Feb 21, 2017 10:38 pm
- Forum: Zero Order Reactions
- Topic: 15.99
- Replies: 2
- Views: 750
Re: 15.99
For second order, half life is t = 1/k[A]initial . Therefore, t (half life) and concentration have 1/[A] relationship.
Whereas, for zero order, half life t = [A]initial/2k , which shows that t(half life) and initial concentration direct linear relationship.
Whereas, for zero order, half life t = [A]initial/2k , which shows that t(half life) and initial concentration direct linear relationship.
- Tue Feb 14, 2017 7:13 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: midterm 2014 Q2D
- Replies: 2
- Views: 528
Re: midterm 2014 Q2D
I am still having a bit of confusion.
So on the problem, on the attached picture, how is the sig fig of the answer determined? Do we just disregard the value that ln becomes? ln(12.90/7.60)
So on the problem, on the attached picture, how is the sig fig of the answer determined? Do we just disregard the value that ln becomes? ln(12.90/7.60)
- Mon Feb 13, 2017 11:56 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: 2014 Midterm
- Replies: 5
- Views: 1086
Re: 2014 Midterm
Ka = [H+][F-]/[HF] and K = [H+]^2[F-]^2]/[HF]^2
therefore, when comparing Ka to K, K is exactly Ka square. Therefore you square root the value K in order to achieve Ka.
therefore, when comparing Ka to K, K is exactly Ka square. Therefore you square root the value K in order to achieve Ka.
- Mon Feb 13, 2017 9:55 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: midterm 2014 Q2D
- Replies: 2
- Views: 528
midterm 2014 Q2D
I am having a bit of confusion for sig figs when ln, e, or log is involved. I am aware that for ln(X), if X has 3 signifiant digits then the value for ln(X) should have 3 decimal places. But in midterm 2014 Q2D, e^4.63 = 102, which also means that ln(102) = 4.63. 4.63 has 2 decimal places. Then, Sho...
- Mon Feb 13, 2017 12:33 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Entropy unit
- Replies: 1
- Views: 448
Entropy unit
So last week in the review session, the TA said that entropy should always be written in Joules and when in kJ we should convert it to J. Is there a specific reason why it has to be in J/Kmol and not kJ/Kmol?
- Fri Feb 10, 2017 2:14 pm
- Forum: Work, Gibbs Free Energy, Cell (Redox) Potentials
- Topic: 2016 WINTER MIDTERM Q8A
- Replies: 1
- Views: 522
Re: 2016 WINTER MIDTERM Q8A
You use subtraction Ecathode-Eanode when they are both in their reduction state. Hence, since the two half reactions are already in oxidation and reduction states, you can add their E° of the both equations. 0.8V+0.4V=1.2V
- Fri Feb 10, 2017 2:08 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterm Review Session- February 9, 6-7PM
- Replies: 2
- Views: 750
- Fri Feb 10, 2017 2:05 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3012821
- Wed Feb 08, 2017 7:08 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Cell Diagrams
- Replies: 3
- Views: 612
Re: Cell Diagrams
Also to add on, anode, reaction losing electron, goes on the left side of the double bar, and cathode, the reaction gaining electrons, goes on the right side of the double bar.
- Tue Jan 31, 2017 1:06 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 1 Preparation Answers
- Replies: 130
- Views: 25228
Re: Quiz 1 Preparation Answers
Can someone explain why in #11 does q go from -23.8 to 23.8? Because -23.8kJ is negative because it was released from converting PbO to Pb. Then, that amount of heat is transferred into the system, which is water. When heat is put into an system, it is an endothermic process and the sign should be ...
- Mon Jan 30, 2017 12:13 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 1 Preparation Answers
- Replies: 130
- Views: 25228
Re: Quiz 1 Preparation Answers
Where do you find the prep quiz?
I only see the midterms from past years.
Do I have to buy a separate booklet or is it in the course reader? Then what page is it in?
I only see the midterms from past years.
Do I have to buy a separate booklet or is it in the course reader? Then what page is it in?
- Wed Jan 25, 2017 12:05 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz Topics
- Replies: 10
- Views: 1845
Re: Quiz Topics
Just for a clear confirmation, then there is nothing due at our discussion sections before our quiz because we are not doing the turn-in quizzes. Is that right?
- Mon Jan 16, 2017 3:35 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3012821
Re: Post All Chemistry Jokes Here
I asked the guy sitting next to me if he had any Sodium Hypobromite…
He said NaBrO
He said NaBrO
- Fri Dec 02, 2016 2:25 pm
- Forum: Significant Figures
- Topic: Sig Figs for pH
- Replies: 3
- Views: 1628
Re: Sig Figs for pH
The previous thread says that we should,
"When working with pH, use the number of sig figs as the number of decimal places in the pH. For example, if the pH=-log(1.8 x 10^-5) then pH = 4.74 (two sig figs in 1.8 x 10^-5, and two after the decimal in 4.74)."
"When working with pH, use the number of sig figs as the number of decimal places in the pH. For example, if the pH=-log(1.8 x 10^-5) then pH = 4.74 (two sig figs in 1.8 x 10^-5, and two after the decimal in 4.74)."
- Thu Nov 17, 2016 12:08 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3012821
Re: Post All Chemistry Jokes Here
Q:Did you hear about the man who got cooled to absolute zero?
A: He's 0K now
A: He's 0K now
Re: Naming
I think so because anything we learned last week is fair game.
- Fri Nov 04, 2016 8:35 am
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3012821
- Thu Oct 27, 2016 9:00 am
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Electron Configurations Stability
- Replies: 1
- Views: 422
Re: Electron Configurations Stability
Having a half full d5 or full d10 subshell has lower energy, therefore, where there is d4 or d9 subshell, it is better to move one electron from the 4s and fill the d subshell.
- Thu Oct 20, 2016 4:14 pm
- Forum: Trends in The Periodic Table
- Topic: Atomic Radius [ENDORSED]
- Replies: 1
- Views: 485
Re: Atomic Radius [ENDORSED]
The different energy levels of the orbitals affect the overall size of the atomic radii. When the elements have the same energy level and orbital, the electrons have affect in the different electrostatic attractions that pertain to each element.
- Fri Oct 14, 2016 11:30 am
- Forum: Photoelectric Effect
- Topic: Photoelectric Effect
- Replies: 5
- Views: 1057
Re: Photoelectric Effect
I think it is nanometer that has been converted to meters.
When you want to convert, for example, 900nm into meters, because there are 1x10^9nm in 1 meter, or 1x10^-9m in 1nm , it would 900nm would be multiplied by 10^-9 to convert into meters.
When you want to convert, for example, 900nm into meters, because there are 1x10^9nm in 1 meter, or 1x10^-9m in 1nm , it would 900nm would be multiplied by 10^-9 to convert into meters.
- Fri Oct 07, 2016 7:42 am
- Forum: Phase Changes & Related Calculations
- Topic: Chemistry Humor
- Replies: 26
- Views: 5436
- Mon Sep 26, 2016 5:34 pm
- Forum: Student Social/Study Group
- Topic: Off Campus/Apartments Study group
- Replies: 5
- Views: 1117
Re: Off Campus/Apartments Study group
I am definitely interested. I can do any day of the week and preferably during the day than the evening.