Search found 26 matches

by Aileen Nguyen 3N
Sat Mar 18, 2017 10:25 pm
Forum: Method of Initial Rates (To Determine n and k)
Topic: Course Reader Final Practice "2016 Final" Q4 part B
Replies: 5
Views: 753

Re: Course Reader Final Practice "2016 Final" Q4 part B

You can see that A does not work because the intermediates do not cancel out the cumulative reactants for B should be 2CLO and O2 since one of the O2's are cancelled out So the two valid ones are B&C Student B: 2ClO; O2 Student C: 2ClO; O2 you can tell that the second steps are the rate limititi...
by Aileen Nguyen 3N
Sat Mar 18, 2017 1:10 pm
Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
Topic: Winter 2013 Final Q4B
Replies: 1
Views: 275

Re: Winter 2013 Final Q4B

[Current] = [Initial] + [Change in initial] [O2] = [O2 initial] + [change in initial O2] Flip both equations: 1 / [O2] = 1 / ([O2 initial] + [change in initial O2]) Since Q = [Products] / [Reactants] = 1 / [O2], plug in: Q = 942.23 = 1 / ([.00117] + [Change in initial O2]) Rearrange and solve using ...
by Aileen Nguyen 3N
Sat Mar 18, 2017 1:06 pm
Forum: General Science Questions
Topic: Winter Final 2013 Q4
Replies: 1
Views: 474

Re: Winter Final 2013 Q4

n is based on the total number of electrons transferred in the redox reaction. Fe2+ goes to Fe, meaning that two electrons are transferred per Fe, and there's a molar coefficient of 2, so in the net reaction we transfer 4 electrons.
by Aileen Nguyen 3N
Sat Mar 18, 2017 12:58 pm
Forum: *Electrophiles
Topic: Is carbon monoxide an electrophile
Replies: 1
Views: 734

Re: Is carbon monoxide an electrophile

Carbon Monixide is an Electorphile. The C=O bond is very polar and the carbonyl carbon is very positive. The carbonyl bond is very polar. There is a partial positive charge on the carbon and a partial negative charge on the oxygen, because oxygen is more electronegative than carbon. This charge sepa...
by Aileen Nguyen 3N
Sat Mar 18, 2017 12:53 pm
Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
Topic: Ch 14 #107
Replies: 1
Views: 322

Re: Ch 14 #107

To relate pH to the equations we learned, E° has to be 0 when pH 7 since pH=7 when concentration of H+ and OH- are equal to 1.0 x 10^-7 mol.L^-1 when k=1 E°is 0 take ∆G°=-nFE°and ∆G°=RTlnK and then you get E°= RT/nF (lnK) at pH=7: K= [H+]/[OH-]= 1.0 x 10^-7 mol.L^-1/1.0 x 10^-7 mol.L^-1= 1 and E = 0...
by Aileen Nguyen 3N
Mon Feb 27, 2017 9:49 pm
Forum: General Science Questions
Topic: Chemisty 14Bl and Chemistry 14C
Replies: 2
Views: 479

Re: Chemisty 14Bl and Chemistry 14C

There are a lot of students in my BL that are in 14C currently and many that haven't taken 14B in over a year and they're doing well!
by Aileen Nguyen 3N
Tue Feb 14, 2017 12:35 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

Happy Valentine's Day!
by Aileen Nguyen 3N
Sun Feb 12, 2017 9:00 pm
Forum: Student Social/Study Group
Topic: Chemistry Joke
Replies: 57
Views: 2300

Re: Chemistry Joke

Great joke!
However, you're supposed to post all chemistry jokes here:
viewtopic.php?f=156&t=4291
by Aileen Nguyen 3N
Mon Feb 06, 2017 5:08 pm
Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
Topic: Homework 14.37
Replies: 1
Views: 281

Re: Homework 14.37

You would use E˚cell = E˚cathode - E˚anode with E˚ at the electrodes being the the electron potential for the half reaction. 2H+ (aq, 1.0 M) +2e- ----> H2 (g, 1 atm) E˚cathode = 0 V H2 (g, 1 atm) ----> 2H+ (aq, .075 M) +2e- E˚anode = 0 V 2H+ (aq, 1.0 M) +2e- + H2 (g, 1 atm) ----> 2H+ (aq, .075 M) +2...
by Aileen Nguyen 3N
Sun Feb 05, 2017 4:07 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

Enjoy!
by Aileen Nguyen 3N
Sun Jan 29, 2017 3:19 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

alcohol is not a problem it's a solution
by Aileen Nguyen 3N
Thu Dec 01, 2016 8:01 pm
Forum: Ionic & Covalent Bonds
Topic: Polarizability
Replies: 2
Views: 307

Re: Polarizability

1) if it is near an anion which has a high charge density (small and high charge)
2) if the cation is large since its electrons will be further away from the protons in its nucleus
by Aileen Nguyen 3N
Thu Dec 01, 2016 7:56 pm
Forum: Bronsted Acids & Bases
Topic: Corrosive Properties
Replies: 1
Views: 318

Re: Corrosive Properties

Acids tend to accept electrons, and bases tend to donate electrons. Acids contain H+ ions. They tend to grab electrons and form hydrogen gas and since metals don't have a tight grip on their electrons. They give them up and the solid metal gradually disappears. The reaction is Bases contain OH- ions...
by Aileen Nguyen 3N
Mon Nov 28, 2016 8:06 pm
Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
Topic: HW #12.69
Replies: 1
Views: 351

Re: HW #12.69

Al3+ forms a complex with water as ligands and since Al3+ is a Lewis acid AlCl3 gets substituted by Al(H2O)6
by Aileen Nguyen 3N
Mon Nov 28, 2016 7:46 pm
Forum: Acidity & Basicity Constants and The Conjugate Seesaw
Topic: Chapter 12 Problem 117
Replies: 1
Views: 308

Re: Chapter 12 Problem 117

A chem moderator said to omit 12.117 :)
by Aileen Nguyen 3N
Mon Nov 28, 2016 7:34 pm
Forum: Equilibrium Constants & Calculating Concentrations
Topic: When to use atm v. bar units [ENDORSED]
Replies: 4
Views: 805

Re: When to use atm v. bar units [ENDORSED]

It would specify if the problem wanted the solution to be in bars
by Aileen Nguyen 3N
Sat Nov 26, 2016 12:31 pm
Forum: Amphoteric Compounds
Topic: Basic, Acidic or Amphoteric [ENDORSED]
Replies: 4
Views: 425

Re: Basic, Acidic or Amphoteric [ENDORSED]

As2O3 is amphoteric because it can react with either acid or base.

Ex. Reaction with Acid
As2O3 we have: As2O3 + 6HCl --> 2AsCl3 + 3H2O

Reaction with base:
NaOH + As2O3 + 3H2O --> 2Na[As(OH)4]
by Aileen Nguyen 3N
Sat Nov 26, 2016 12:55 am
Forum: Non-Equilibrium Conditions & The Reaction Quotient
Topic: 11.67
Replies: 1
Views: 360

Re: 11.67

Reactants are strongly favored so we push the reaction as far to the left as possible and then start from the new initial conditions Pressures (bar) 2 HCl(g) -> H2(g) + Cl2(g) Original 2.0 1.0 3.0 New initial 4.0 0.0 2.0 Change -2x +x +x Final 4.0-2x +x 2.0-x K= PH2 PCl2 / PHCl2 3.2 x 10 ^-34 = x(2....
by Aileen Nguyen 3N
Mon Nov 14, 2016 11:12 am
Forum: Equilibrium Constants & Calculating Concentrations
Topic: Equilibrium Concentration Units [ENDORSED]
Replies: 3
Views: 731

Re: Equilibrium Concentration Units [ENDORSED]

You would use molarity as the units when calculating equilibrium concentrations!
by Aileen Nguyen 3N
Mon Nov 14, 2016 11:07 am
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

-
by Aileen Nguyen 3N
Tue Nov 01, 2016 11:45 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

Accurately portrays my love life
by Aileen Nguyen 3N
Sun Oct 30, 2016 4:01 pm
Forum: Lewis Structures
Topic: H/W Q: 3.51- The Lewis stucture of HClO?
Replies: 1
Views: 449

Re: H/W Q: 3.51- The Lewis stucture of HClO?

HClO is an oxoacid and in oxoacids hydrogen has to be bonded with oxygen.
by Aileen Nguyen 3N
Thu Oct 20, 2016 10:55 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7569
Views: 1011659

Re: Post All Chemistry Jokes Here

A photon checks into a hotel and is asked if he needs an help with his luggage.
He replies " No, I'm traveling light."
by Aileen Nguyen 3N
Sat Oct 15, 2016 3:48 pm
Forum: Electron Configurations for Multi-Electron Atoms
Topic: 3d and 4s orbitals
Replies: 2
Views: 640

Re: 3d and 4s orbitals

3D is only lower in energy than 4s after the 4s orbital is occupied
by Aileen Nguyen 3N
Thu Oct 06, 2016 4:32 pm
Forum: Properties of Light
Topic: Atomic Spectra- Question 1.15 [ENDORSED]
Replies: 3
Views: 519

Re: Atomic Spectra- Question 1.15 [ENDORSED]

I solved this problem using the Rydberg equation instead of the bohr frequency condition.

You solved the n1=1 so for a line that's 102.6 nm you use the formula v=c/(lambda) = 2.922 x10^15 s^-1

Then use the Rydberg to solve for n2 which would give you n2=3
by Aileen Nguyen 3N
Sun Oct 02, 2016 10:23 pm
Forum: Student Social/Study Group
Topic: CHEM JOKES
Replies: 29
Views: 3480

Re: CHEM JOKES

Do you have 11 protons? Cause your sodium fine.

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