Search found 15 matches

by garrett_perozich
Sat Mar 18, 2017 5:44 pm
Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
Topic: Winter 2015 Final #9A [ENDORSED]
Replies: 4
Views: 1140

Re: Winter 2015 Final #9A [ENDORSED]

Why is the substituent given priority in regards to naming? In other words, why wouldn't it be 3-(3-chlorocycloheptnyl)-2-methylpropan-1-ol? I thought that the functional group always receives the lowest number.
by garrett_perozich
Fri Mar 17, 2017 5:05 pm
Forum: Reaction Mechanisms, Reaction Profiles
Topic: Having pre-equilibrium in final answer
Replies: 1
Views: 185

Re: Having pre-equilibrium in final answer

No, you wouldn't. As long as you specified within your work that that was what K was equal to, then you should be fine.
by garrett_perozich
Fri Mar 17, 2017 4:20 pm
Forum: *Alcohols
Topic: Numbering alcohols
Replies: 2
Views: 589

Numbering alcohols

Is 4,4-dimethyl-2-hexanol the same thing as 4,4-dimethylhexan-2-ol? In other words, can we number the location of the alcohol before the "ol" and have it represent the same molecule as if we numbered before the longest carbon chain?
by garrett_perozich
Mon Mar 13, 2017 9:40 pm
Forum: Entropy Changes Due to Changes in Volume and Temperature
Topic: Final Exam 2013 Question 1B
Replies: 1
Views: 263

Final Exam 2013 Question 1B

For 1B, how would a student know to use Cv for step 2? I understand that you would either use Cv or Cp since the problem told you to treat it as an ideal gas, but what doesn't make sense to me is why you'd use Cv if they volume was not constant (it changes from 3.0 to 3.5L). Also, the pressure isn't...
by garrett_perozich
Sat Mar 11, 2017 4:33 pm
Forum: Arrhenius Equation, Activation Energies, Catalysts
Topic: Catalyst that is used and produced
Replies: 4
Views: 519

Catalyst that is used and produced

On quiz two, we had a reaction with two steps:

Step 1: this was the slow step and used a catalyst
Step 2: this was a fast step and produced the same catalyst

So my question is, why would the catalyst be a part of the rate law equation if it is produced as soon as it is used up?
by garrett_perozich
Sun Mar 05, 2017 5:19 pm
Forum: *Electrophilic Addition
Topic: Page 152 of organic textbook
Replies: 2
Views: 610

Re: Page 152 of organic textbook

If you draw it out, you will see why it gets a partial positive charge. Look at the bonds. Our middle carbon (the one you're talking about with the positive charge) is bonded to a carbon on the left (1 bond), + a carbon on the right (now we have 2 bonds), and then a hydrogen (that's 3 bonds). But ou...
by garrett_perozich
Sun Mar 05, 2017 5:16 pm
Forum: *Organic Reaction Mechanisms in General
Topic: number of steps in reaction mechanism
Replies: 1
Views: 285

Re: number of steps in reaction mechanism

The difference between these two is that, in problem 34, we are given the products, and as we can see, our hydroxide stays as a hydroxide. So, this would only be one step, since our O is still bonded to our H. In 26, we have to first break our HI up and attach our H to the carbon, but we now have an...
by garrett_perozich
Sun Mar 05, 2017 5:14 pm
Forum: *Organic Reaction Mechanisms in General
Topic: Problem 28 Ch. 4
Replies: 2
Views: 327

Re: Problem 28 Ch. 4

The molecules would need to collide again for this next step to happen.
by garrett_perozich
Sun Mar 05, 2017 5:13 pm
Forum: *Free Energy of Activation vs Activation Energy
Topic: Self Test 4.4A part c
Replies: 1
Views: 848

Re: Self Test 4.4A part c

When you look at the activation energies, you are looking at the energy needed to move from its previous "state" to the new transition state (TS). So, for Ea1, it is from the reactants "axis", to the top of TS1. For Ea2, though, we have to look at the difference between the inter...
by garrett_perozich
Sun Mar 05, 2017 5:07 pm
Forum: *Organic Reaction Mechanisms in General
Topic: Sign of the Gibbs for a reaction profile
Replies: 3
Views: 456

Sign of the Gibbs for a reaction profile

When drawing a reaction profile given the equation, for example, CH3CHCH2 + HBr, how do we know whether the final Gibbs free energy will be lower or higher than the initial? We were asked to do this twice on the homework for chapter 4, once for Gibbs, and the other for potential, and both times I as...
by garrett_perozich
Sat Mar 04, 2017 10:38 pm
Forum: *ChemDraw
Topic: Curved arrow [ENDORSED]
Replies: 1
Views: 571

Re: Curved arrow [ENDORSED]

Curved arrows are used to represent the transfer of a pair of electrons. So while it may be used for a bond, in which case it would represent the transfer of the two electrons that are being shared between the atoms for that particular bond, it may also be used on a lone pair of electrons, in which ...
by garrett_perozich
Thu Feb 23, 2017 8:29 pm
Forum: Student Social/Study Group
Topic: Post All Chemistry Jokes Here
Replies: 7951
Views: 1215279

Re: Post All Chemistry Jokes Here

I tell chemistry jokes periodically, but usually there is no reaction.
by garrett_perozich
Thu Feb 16, 2017 12:01 pm
Forum: Second Order Reactions
Topic: Disregarding Products and Focusing on Reactants
Replies: 2
Views: 354

Re: Disregarding Products and Focusing on Reactants

If you take a look at page 59 in the course reader, we aren't really "ignoring" the products. As seen at the top of the page, the rate that the reactants decrease is equal to the rate that the products increase (with the opposite sign). Also, it is easier to study an initial reaction when ...
by garrett_perozich
Wed Feb 08, 2017 8:30 pm
Forum: Van't Hoff Equation
Topic: HW 11.111
Replies: 1
Views: 250

Re: HW 11.111

Hi, The book actually doesn't divide by 100. We know that K1 is 10x greater than K2. So that means that K1 = 10*K2. Now if we do K1/K1, substituting 10*K2 for K1, we get 10*K2/K2, or 10, since the K2's cancel. Now, that value is a constant for our equilibrium value when solving for our Gibbs Free En...
by garrett_perozich
Thu Feb 02, 2017 6:53 pm
Forum: Administrative Questions and Class Announcements
Topic: Quiz 1 Preparation Answers
Replies: 130
Views: 16770

Re: Quiz 1 Preparation Answers

#8 on Quiz 1 Preparation says, "For reaction: 2C+2H2=C2H4, DeltaH= +52.3 kJ/mol and DeltaS= -53.07 J/K*mol at 298 K. At what temperature will this reaction be spontaneous?" Initially, I thought the formula needed to solve for the temperature was DeltaG= DeltaH - T*DeltaS but then I saw th...

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