Search found 13 matches
- Fri Mar 17, 2017 4:43 pm
- Forum: *Cyclohexanes (Chair, Boat, Geometric Isomers)
- Topic: Cis vs trans
- Replies: 1
- Views: 418
Re: Cis vs trans
Yes, because they are opposite from eachother therefore they won't be bumping into eachother or causing strain or anything.
- Fri Mar 17, 2017 4:43 pm
- Forum: *Cyclohexanes (Chair, Boat, Geometric Isomers)
- Topic: Cis Trans
- Replies: 3
- Views: 1632
Re: Cis Trans
Cis is the same side, and trans is opposite sides. You have to look at the two highest priority groups. So for example, if you are looking at a double bond and the two highest priority groups (most complex molecules) are on the same side (both up) or both down, then it is Cis. Trans is across from e...
- Sun Mar 12, 2017 7:55 pm
- Forum: *Constitutional and Geometric Isomers (cis, Z and trans, E)
- Topic: Geometric isomers as line structures
- Replies: 4
- Views: 920
Re: Geometric isomers as line structures
Hi!!!!!!!!!!!!!!!!!!!!!!!!
If the two highest priority groups are on the same side, then it's a cis geometric isomer.
If the two highest priority groups are on opposite sides, then it is a trans geometric isomer.
Page 16 in the Green textbook thingy at the bottom.
If the two highest priority groups are on the same side, then it's a cis geometric isomer.
If the two highest priority groups are on opposite sides, then it is a trans geometric isomer.
Page 16 in the Green textbook thingy at the bottom.
- Mon Mar 06, 2017 1:16 pm
- Forum: *Alkanes
- Topic: Drawing/Labeling reaction profile
- Replies: 3
- Views: 762
Drawing/Labeling reaction profile
When drawing the diagram with the two bumps (TS 1 and TS2), how do you know if the reaction is going to be endothermic or exothermic? The reactants will be higher on the diagram than the products if it is exothermic, but how do I know if it's exothermic?
Is it based on how many bonds break/form?
Is it based on how many bonds break/form?
- Sun Mar 05, 2017 12:10 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 2 Winter 2017
- Replies: 160
- Views: 25394
Re: Quiz 2 Winter 2017
For Quiz 2, does ln(A) represent the final concentration (what's left over) or does it represent the change in concentration, and then you would have to subtract from the original amount to get the final concentration?
- Sun Mar 05, 2017 12:06 pm
- Forum: *Electrophiles
- Topic: BF3 and NF3
- Replies: 3
- Views: 4057
Re: BF3 and NF3
Boron has an empty 2p orbital and a strong positive charge on the boron atom (because Fluorine is electronegative)
So yes, BF3 is an electrophile.
Unlike BF3, NF3 is a Lewis Base, and it won't accept electron pairs from other species.
That's my understanding of it, but I could be wrong.
So yes, BF3 is an electrophile.
Unlike BF3, NF3 is a Lewis Base, and it won't accept electron pairs from other species.
That's my understanding of it, but I could be wrong.
- Sun Feb 19, 2017 1:05 pm
- Forum: Kinetics vs. Thermodynamics Controlling a Reaction
- Topic: Calculating order for a reaction
- Replies: 1
- Views: 474
Re: Calculating order for a reaction
Hi, yes it's the reactants. 0th order: rate = k[A]^0 1st order: rate= k[A]^1 2nd Order: rate=k[A]^2 The overall order of the reaction can be found by adding the exponents of the reactants. Here's a Khan Academy video that helped me: https://www.khanacademy.org/science/chemistry/chem-kinetics/reactio...
- Sat Feb 11, 2017 6:27 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Midterm 2016 Question 8B [ENDORSED]
- Replies: 5
- Views: 963
Midterm 2016 Question 8B [ENDORSED]
On Question 8B on the 2016 Midterm, the answer says the potential of the cell would increase, because Cadmium ions are taken out of the solution, and the equilibrium will favor the products, driving the reaction forward.
Why does the cell potential increase when the reaction is driven forward?
Why does the cell potential increase when the reaction is driven forward?
- Sun Feb 05, 2017 12:27 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Oxidation/Reaction Question
- Replies: 2
- Views: 510
Re: Oxidation/Reaction Question
Another phrase that might help you remember is
LEO says GER
Losing Electrons = oxidation.
Gaining Electrons = Reduction.
Hope this helps too!
LEO says GER
Losing Electrons = oxidation.
Gaining Electrons = Reduction.
Hope this helps too!
- Sun Jan 29, 2017 4:01 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Bond Enthalpy [ENDORSED]
- Replies: 2
- Views: 682
Re: Bond Enthalpy [ENDORSED]
My TA said that it might be easier to just break all the bonds and reform all the bonds. Its been working for me so far and it's a lot easier to remember. Also this is the only case where its reactants - products instead of the other way around.
- Sun Jan 29, 2017 3:55 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Quiz 1 Study Group
- Replies: 1
- Views: 436
Re: Quiz 1 Study Group
hi me and meghna duh
- Sun Jan 22, 2017 3:37 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: HW 8.41
- Replies: 3
- Views: 671
Re: HW 8.41
You would have to do it in several steps.
Q(ice) = Q(ice1) + Q(ice2)
Q(ice) + Q(water) = 0
To find Q(ice1) : (50g/18.02g)*(6.01x10^3 J/mol)
Q(ice2): m*Cwater*T
Q(water) = m*Cwater*T
You'd plug in the values using the Appendixes and then you should get your answer.
Q(ice) = Q(ice1) + Q(ice2)
Q(ice) + Q(water) = 0
To find Q(ice1) : (50g/18.02g)*(6.01x10^3 J/mol)
Q(ice2): m*Cwater*T
Q(water) = m*Cwater*T
You'd plug in the values using the Appendixes and then you should get your answer.
- Sun Jan 15, 2017 1:17 pm
- Forum: Phase Changes & Related Calculations
- Topic: Phase Change
- Replies: 3
- Views: 628
Phase Change
What are the different equations for phase-change vs non-phase change when you're looking at the graph of temperature on heat? (Like, the sloped part of the graph vs the flat part of the graph?)