Search found 11 matches
Search found 11 matches • Page 1 of 1
I think Grace is asking why the ketone functional group has a lower carbon number than the methyl groups since we've learned that functional groups have the highest priority in carbon numbering. Why isn't it 4-dimethyl-3-pentanone instead?
- Wed Mar 15, 2017 2:18 pm
- Forum: *Cycloalkanes
- Topic: Numbering counterclockwise or clockwise
- Replies: 4
- Views: 3599
I have a related question - what if there is a functional group as well as a double bond? I know that the carbon attached to the functional group would be the first one but if the double bond isn't attached to that same first carbon, which was does the numbering go? Or does it not matter?
- Wed Mar 15, 2017 2:04 pm
- Forum: Student Social/Study Group
- Topic: Chem 14C Discussion Swap
- Replies: 3
- Views: 651
Hi all, I have a similar problem, I'm currently enrolled in Disc 1L but can switch to 1A, B, D, E, F, H, M, or O. Please let me know if you can switch, thanks!
I know substituents must be written alphabetically but when there are halides with additional alkyl substituents, do they halides always come first (alphabetically) followed by all the alkyl groups (alphabetically)? For example would it be 3-iodo-4-ethyl... Or 4-ethyl-3-iodo... ?
- Sun Mar 12, 2017 11:16 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Saying Thank You to Dr. Lavelle
- Replies: 282
- Views: 134888
Dear Dr. Lavelle, Being a student this quarter in Chem 14B has been more enjoyable than I ever thought it would be. I'm constantly impressed and inspired by the time and effort you put in to making sure we succeed even though you can't possibly know all of us personally! Your commitment to the subje...
- Mon Feb 20, 2017 10:25 pm
- Forum: Zero Order Reactions
- Topic: Quiz 2 Prep (#7 from Winter 2016)
- Replies: 1
- Views: 345
I'm having some trouble understanding this question and the answer: Q: Which one of the following is true for a reaction that has only one reactant? A) If the reaction is first order, then t1/2 will double as the initial concentration of the reactant doubles. B) If the reaction is zero order, then t...
- Fri Feb 17, 2017 9:41 pm
- Forum: General Rate Laws
- Topic: Presence of a Catalyst
- Replies: 1
- Views: 304
hi matt! Step by step reactions with catalysts look like this (the catalyst cancels out in the final balanced equation): Step 1: A + Cat. --> Int. Step 2: Int. + B --> D + Cat. Final: A + B --> D when a catalyst is added, the energies of R and P are unaffected, only the activation energy (Ea) is aff...
- Sat Feb 04, 2017 5:17 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Calculating Heat [ENDORSED]
- Replies: 2
- Views: 395
Yes, it's definitely referring to the heat needed switch to another state of matter (I.e. Gas to liquid or liquid to solid, calculated with nHf) in addition to the heat needed to get the final state of matter to the desired temperature (that part is just mc(tf-ti)).