If the substance you are dealing with is a monatomic ideal gas, then you can substitute Cp for 5/2R and Cv for 3/2R.
Hope this helps!
Search found 22 matches
- Wed Mar 15, 2017 5:00 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: 5/2R vs 3/2R
- Replies: 2
- Views: 372
- Mon Mar 06, 2017 6:52 pm
- Forum: *Alkanes
- Topic: Iso and Neo Prefixes
- Replies: 5
- Views: 793
Re: Iso and Neo Prefixes
Iso- is used to name a substituent chain that has a specific orientation of carbon and hydrogen atoms, (CH 3 ) 2 CH-. You would then determine the name of the whole substituent based on how many total carbon atoms there are in the entire structure. Neo- is the same as Iso- with respect to naming a s...
- Tue Feb 28, 2017 4:08 pm
- Forum: *Alkanes
- Topic: 4-ethyl-2,2-dimethylhexane vs 2,2-dimethyl-4-ethylhexane
- Replies: 2
- Views: 792
Re: 4-ethyl-2,2-dimethylhexane vs 2,2-dimethyl-4-ethylhexane
The order is based on the first letter of the individual substituents regardless of the prefix in front. In other words, for dimethyl, it is the "m" that is ordered and not the "d." Therefore, ethyl would be written before methyl in the naming of the compound rather than the othe...
- Thu Feb 23, 2017 11:42 pm
- Forum: *Electrophiles
- Topic: BF3
- Replies: 2
- Views: 497
Re: BF3
Yes because the central Boron atom in molecule only has 6 electrons and would want to complete its octet, so therefore it would be an electrophile.
- Tue Feb 14, 2017 12:41 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: 14.85
- Replies: 1
- Views: 259
Re: 14.85
This is because reducing power is the ability of an element to cause another element to be reduced, in other words, it is asking for the best reducing agent out of all of the elements listed. This means that the element that has the lowest reduction potential would have the higher reducing power bec...
- Sun Feb 12, 2017 10:40 am
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Ssurroudnings vs Ssystem
- Replies: 1
- Views: 293
Re: Ssurroudnings vs Ssystem
You would add the negative sign relative to which \Delta S you are looking at. For example, if you were looking at \Delta S surr and the reaction taking place is endothermic, then that means heat is being lost from the surroundings and going into the system, which means that the surroundings are los...
- Sun Feb 12, 2017 10:35 am
- Forum: Balancing Redox Reactions
- Topic: Adding H20 AND H+
- Replies: 3
- Views: 1521
Re: Adding H20 AND H+
You add H2O molecules to a half reaction to help balance out the number of oxygens each side of the reaction has. Similarly, you would add H+ ions to help balance out the number of hydrogens there are on each side of the equation.
Hope this helps!
Hope this helps!
- Sun Feb 05, 2017 10:13 pm
- Forum: Balancing Redox Reactions
- Topic: Oxidation [ENDORSED]
- Replies: 4
- Views: 924
Re: Oxidation [ENDORSED]
The oxidizing agent of a reaction is the element that receives the electron(s) that are lost by the element that is being oxidized in the reaction. In other words, it is the element that is being reduced in the reaction. As for the reducing agent, it's the exact opposite. It is the element that give...
- Fri Feb 03, 2017 11:37 pm
- Forum: Balancing Redox Reactions
- Topic: Standard reduction potential (E)
- Replies: 2
- Views: 487
Re: Standard reduction potential (E)
It'll vary depending on the situation. The cathode/anode of a reaction depends whether or not the elements in a reaction are reduced or oxidized, respectively. It's not always a given that the cathode half-reaction will be positive and the anode negative.
- Fri Jan 27, 2017 5:54 pm
- Forum: Concepts & Calculations Using First Law of Thermodynamics
- Topic: Enthalpy Units
- Replies: 1
- Views: 342
Re: Enthalpy Units
When the units are just kJ, it usually is written at the end of a reaction on the same line and it's implied that value of enthalpy is the change in energy for one "mole" of reaction. For example, if you were to double the amount of reactants/products, it would use twice the amount of enth...
- Wed Jan 11, 2017 7:08 pm
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Ch.8 Exercise 31
- Replies: 2
- Views: 352
Re: Ch.8 Exercise 31
You will need to use the q=mc\Delta T equation and plug in the values you are given, the mass, heat capacity constant for Krypton, and the change in temperature. The reason for there being two different heat capacities is because the heat capacity constant for any substance is different depending on...
- Wed Nov 30, 2016 5:03 pm
- Forum: *Indicators
- Topic: Importance of Indicators
- Replies: 2
- Views: 3569
Re: Importance of Indicators
The main thing about indicators is that they cause the solution you are titrating to change color when you reach the stoichiometric point of a titration. There's a bunch of different indicators with different pK ln values and you have to strategically select an indicator that has a pK In value that ...
- Mon Nov 21, 2016 5:49 pm
- Forum: Acidity & Basicity Constants and The Conjugate Seesaw
- Topic: Why when given Ka = weak acid
- Replies: 7
- Views: 1744
Re: Why when given Ka = weak acid
This is because the K a is an equilibrium constant for the dissociation of the acid in water. If you're given any value of K a , then that means not all of the acid has dissociated when the acid placed in water and there are still molecules of the acid inside of the water, along with some small conc...
- Wed Nov 16, 2016 7:07 pm
- Forum: Lewis Acids & Bases
- Topic: question regarding lecture today
- Replies: 1
- Views: 407
Re: question regarding lecture today
We won't see the equilibrium constant because HCl dissociates completely in water, meaning that all of the HCl "splits" into H + and Cl - and therefore there won't be any HCl molecules left in the water after the reaction is finished. Therefore, there won't be any reactants left and the eq...
- Tue Nov 15, 2016 5:20 pm
- Forum: Naming
- Topic: Number 29 from the Hw [ENDORSED]
- Replies: 4
- Views: 518
Re: Number 29 from the Hw [ENDORSED]
Woops my bad, it would be ferrate because the overall charge on the compound is negative so you would add the -ate ending on the metal to reflect that.
- Sun Nov 06, 2016 7:56 pm
- Forum: Naming
- Topic: Number 29 from the Hw [ENDORSED]
- Replies: 4
- Views: 518
Re: Number 29 from the Hw [ENDORSED]
Finding the oxidation number of metals is generally pretty straightforward as you would just subtract the overall charge of the compound by any negatively charged ligands located between the brackets (for the iron compound, there are 6 CN - molecules so subtract that from -4 gives a 2+ charge for th...
- Thu Oct 27, 2016 8:00 pm
- Forum: Hybridization
- Topic: 5 bonds - sp3d??? [ENDORSED]
- Replies: 2
- Views: 816
Re: 5 bonds - sp3d??? [ENDORSED]
This is because there are only 3 different p "sub-orbitals" (p x , p y , p z ) and when all three hybridize with an s orbital, the highest number of hybrid orbitals that can be produced is four, meaning that the four hybrid orbitals can only support a molecule that has four regions of elec...
- Sun Oct 23, 2016 1:17 am
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Textbook question 3.5
- Replies: 1
- Views: 356
Re: Textbook question 3.5
This is because copper's electron configuration is special in that it takes one of the electrons from its 4s orbital and moves it to its 3d orbital so that the 3d orbital contains 10 electrons and is therefore in a more stable configuration. As a result, the configuration of copper is [Ar]3d 10 4s 1...
- Thu Oct 13, 2016 11:21 am
- Forum: Molarity, Solutions, Dilutions
- Topic: Workbook Page 11 Number 5
- Replies: 2
- Views: 533
Re: Workbook Page 11 Number 5
The placement of the period is a little bit off in the equation. The dot is meant to be a little higher up and in between Copper(II) Sulfate and 5 Water and is meant to be a sort of "multiplication dot" that indicates that the compound is a type of hydrate, hence the additional 5 water mol...
- Wed Oct 05, 2016 4:04 pm
- Forum: Properties of Light
- Topic: 1.69 Homework Problem [ENDORSED]
- Replies: 2
- Views: 703
Re: 1.69 Homework Problem [ENDORSED]
The agents have to choose the laser that best mimics the original laser in regards to it being able to discharge electrons from the surface of the lithium cell. This is because if the beam is broken or if the laser has less energy than the original one, the alarm will go off (indicating that no elec...
- Fri Sep 30, 2016 4:25 pm
- Forum: Properties of Light
- Topic: Magnetic and Electric fields
- Replies: 4
- Views: 538
Re: Magnetic and Electric fields
I think it's referring to the electric field.
- Fri Sep 30, 2016 4:24 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: 1.57 [ENDORSED]
- Replies: 5
- Views: 1161
Re: 1.57 [ENDORSED]
The wavelengths listed correspond to the different wavelengths an electron can absorb at each energy level (i.e. 653.6 nm for n = 1, 486.1 for n = 2, etc.). Since it's asking for the next wavelength in the series, you would need to find the energy difference of the electron at n = 5 since you're giv...