Hello,
I was working on question 9B on the Winter 2015 final and they named the OH functional groups as hydroxy functional groups instead of alcohols? Can someone explain why this is and how we can tell the difference? Thanks!
Search found 17 matches
- Sat Mar 18, 2017 10:47 pm
- Forum: *Alcohols
- Topic: Hydroxy vs Alcohol?
- Replies: 2
- Views: 2623
- Sun Mar 12, 2017 8:29 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Winter 2013 Final Q3C
- Replies: 2
- Views: 605
Winter 2013 Final Q3C
Hey everyone,
Why is is that the Faraday constant is not included in the equation that the solution uses? Instead, they only use the n in the equation. Thanks!
Why is is that the Faraday constant is not included in the equation that the solution uses? Instead, they only use the n in the equation. Thanks!
- Mon Mar 06, 2017 8:29 am
- Forum: *Nucleophiles
- Topic: Alkyl vs Aryl Carbanion
- Replies: 2
- Views: 1514
Re: Alkyl vs Aryl Carbanion
Hi Sarahi, Aryl carbanions are aromatic (ring) compounds made of carbon that have lost a hydrogen and now contain a lone pair of electrons. They are sp2 hybridized. Alkyl carbanions are non aromatic, so the carbons are bonded in a chain, and the carbon has lost its bond with a hydrogen and now has a...
- Sun Feb 26, 2017 5:36 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3043340
Re: Post All Chemistry Jokes Here
I cringed so hard but here it is
If H20 is the formula for water, what is the formula for ice?
H20 cubed
If H20 is the formula for water, what is the formula for ice?
H20 cubed
- Wed Feb 22, 2017 2:22 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: Rate Determining Step
- Replies: 3
- Views: 730
Re: Rate Determining Step
Hi there,
Intermediates are not included in the overall rate law because intermediates are not final products. So because intermediates are not observable, they are not included in the rate law that is determined experimentally. Hope that helps!
Intermediates are not included in the overall rate law because intermediates are not final products. So because intermediates are not observable, they are not included in the rate law that is determined experimentally. Hope that helps!
- Sun Feb 19, 2017 10:37 pm
- Forum: Second Order Reactions
- Topic: Homework Problem 15.19
- Replies: 3
- Views: 741
Homework Problem 15.19
Hi guys,
I was doing question 15.19 and I was having trouble finding the order of the reaction of B. According to the solutions manual, the reaction is second order in B, but I don't understand what steps they took to get that answer so any clarification would be much appreciated. Thanks!
I was doing question 15.19 and I was having trouble finding the order of the reaction of B. According to the solutions manual, the reaction is second order in B, but I don't understand what steps they took to get that answer so any clarification would be much appreciated. Thanks!
- Sun Feb 12, 2017 8:25 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Midterm 2016, Question 2
- Replies: 2
- Views: 548
Midterm 2016, Question 2
Hello,
I was wondering why and how the temperature is converted from degrees celsius to K on question 2 from the 2016 midterm? I thought that you converted degrees celsius by adding 273 K to it, but the questions says that -70 degrees celsius is the same as -70 K..? Thanks!
I was wondering why and how the temperature is converted from degrees celsius to K on question 2 from the 2016 midterm? I thought that you converted degrees celsius by adding 273 K to it, but the questions says that -70 degrees celsius is the same as -70 K..? Thanks!
- Mon Jan 30, 2017 1:28 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 1 Preparation Answers
- Replies: 130
- Views: 25409
Re: Quiz 1 Preparation Answers
Can someone please explain why on #5 the answer has 2NH3 on the product side? When I did the question and canceled everything, I divided 2NH3 by 2 so that it would be the same as in the target equation N2H4 + H2 = NH3. This gave me an enthalpy of -105.1kJ/mol, instead of -151 kJ/mol. Thanks
- Sun Jan 22, 2017 3:25 pm
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: 8.31 Monatomic Gas
- Replies: 1
- Views: 392
8.31 Monatomic Gas
In the question, it mentions that Kr is a monatomic gas and I was wondering what exactly is a monatomic gas? I checked in the textbook and it mentions that the molar internal energy of a monatomic ideal gas is 3/2RT. Basically, I was wondering why the internal energy formula is different for a monat...
- Wed Nov 16, 2016 8:57 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Ligands and Coordination Numbers
- Replies: 2
- Views: 732
Re: Ligands and Coordination Numbers
Hi, I had a question that I thought would be relevant to this topic. I was simply wondering whether or not elements that are not contained within the brackets or are directly bonded to the transition metal (like ligands) could also be factored into the coordination number? Thanks!
- Tue Nov 15, 2016 7:44 pm
- Forum: Naming
- Topic: Quizlet for the names of Common Ligands
- Replies: 10
- Views: 2202
Re: Quizlet for the names of Common Ligands
Wow this was really helpful! Thanks for making it!
- Tue Nov 08, 2016 9:08 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: MO theory
- Replies: 3
- Views: 724
Re: MO theory
How is it possible to have bond orders of 1.5, 2.5, etc? Does it have anything to do with resonance structures?
- Sat Oct 29, 2016 7:10 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Exceptions for Electron Configurations
- Replies: 3
- Views: 3638
Re: Exceptions for Electron Configurations
Hey Yuni, When referring to the ground state electron configuration of an atom, it simply means it is the electron configuration of an atom at its lowest energy level. In contrast, an atom in an excited state has absorbed additional energy. I have added a link below that might help you out a bit bet...
- Sat Oct 22, 2016 9:23 pm
- Forum: Electronegativity
- Topic: Difference between electron affinity and electronegativity
- Replies: 3
- Views: 2138
Re: Difference between electron affinity and electronegativity
Hey there, I just wanted to share this diagram with you because it really helped me memorize the trends of electron affinity and electronegativity on the periodic table. I hope it helps you put things into perspective! http://2012books.lardbucket.org/books/principles-of-general-chemistry-v1.0/sectio...
- Mon Oct 10, 2016 9:37 pm
- Forum: Significant Figures
- Topic: All students read this sig fig post [ENDORSED]
- Replies: 170
- Views: 33703
Re: All students read this sig fig post [ENDORSED]
Ariana, I believe that only the final answer has to have the correct number of sig figs and you use exact calculations throughout the problem to make sure your answer is accurate, but anyone feel free to correct me if I'm wrong.
- Mon Oct 10, 2016 9:23 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Quiz 1 Preparation: Fall 2014 Question #10 [ENDORSED]
- Replies: 6
- Views: 1306
Re: Quiz 1 Preparation: Fall 2014 Question #10 [ENDORSED]
So, just to clarify, you got 7.55 x 10^-20 by using E=hv and plugging in the given frequency? Also, can you explain how canceling the negatives works out to n=6? Thanks!
- Wed Sep 28, 2016 3:51 pm
- Forum: Photoelectric Effect
- Topic: Photoelectric effect pre-module assessment #17-19
- Replies: 8
- Views: 1610
Re: Photoelectric effect pre-module assessment #17-19
Can you explain the concept behind #18? I thought that the work function was exactly the same as the threshold energy (energy needed to remove electrons) so I don't quite understand what is being done. Thanks