CHEMISTRY COMMUNITY

Sydmon Nguyen-Tran 1N

It is trans because if you're looking at the C-C double bond alone, and the rest of the chain as a substituent, then the bottom right substituent would be 2methyl-butane and the top left would be ethyl, which have higher priorities than the methyls on the top right and bottom left, therefore it is t...

Sydmon Nguyen-Tran 1N

Page 16 Toolbox 1.1 in the Introduction to Organic Chemistry explains how to determine priority. It says that priority is based on the atomic number of the atom bound to the sp2 carbon atom; so for 1.26, Br has an atomic number 35 while the methyl group has less priority than the ethyl group sharing...

Sydmon Nguyen-Tran 1N

Okay that clears things up. Thank you

Sydmon Nguyen-Tran 1N

What are the significant differences between the formation of an (S)-isomer and an (R)-isomer?

Sydmon Nguyen-Tran 1N

The hydrolysis of sucrose in acid solution is third-order, r = k[sucrose][H+][H2O]; however, the concentrations of both the catalyst H+ and the solvent H2O are normally constant, so that the reaction is pseudo–first-order.

Sydmon Nguyen-Tran 1N

Reaction Rate is the change in concentration of reactants or the change in concentration of products divided by the time interval over which the change takes place. The rate constant (k) for the reaction is characteristic of the reaction (different reactions have different rate constants) and the te...

Sydmon Nguyen-Tran 1N

It's actually supposed to be 0.025693V and it comes from calculating RT/F. It's really just a constant by multiplying other constants together.

Sydmon Nguyen-Tran 1N

This is from a post about a year ago: "S(gas) >> S(liquid) > S(solid), always. For the same state, to compare entropy, think of the equation S = klnW (where k is Boltzmann's constant). W = (number of states)^(number of particles). With the same amount of moles, monatomic gases have more entropy...

Sydmon Nguyen-Tran 1N

I believe it's because on option C, the heat capacities for the solid and gas are better represented in that they are more equal in slope and length than compared to option B

Sydmon Nguyen-Tran 1N

Are the Born-Haber Cycle and lattice enthalpy going to be applied during this course?

Sydmon Nguyen-Tran 1N

When drawing out the Lewis structures for the reactants, it can be seen that the only bonds broken are between the C=C of the CH2 molecules and the bond between the H and Br atom. For the products, only one C-H bond is formed from the broken bond in the reactants, which is taken into account in the ...

Sydmon Nguyen-Tran 1N

It's essentially the same equation, but using base and conjugate acid:
ph=pKb + log (conjugate acid concentration / concentration of b) or
ph=pKb + log (BH^+/B)

Sydmon Nguyen-Tran 1N

If the pressure of a system is INCREASED, the reaction will shift toward the side with fewer moles of GAS. If the pressure of a system is DECREASED, the reaction will shift toward the side with more moles of GAS. If the moles of gas reactants is equal to the moles of gas reactants, a change in press...

Sydmon Nguyen-Tran 1N

I'm pretty certain that part c is very similar to calculating the equilibrium composition where you are given the initial pressure, in this case .10 bar, and you are trying to find the change in pressure to get the equilibrium decomposition pressure.

Sydmon Nguyen-Tran 1N

When drawing MO diagrams for atoms in Period 3, is it necessary to draw the 2nd shell Molecular orbitals in addition to the 3rd shell molecular orbitals?

Sydmon Nguyen-Tran 1N

Because the nuclear charge is less, the energy difference between the filled s-orbital and p-orbitals is less. Remembering that the electron density from filled sigma(s) and sigma*(s) orbital is concentrated along the bond axis, and since the sigma(Pz) orbital is also directed along bond axis, there...

Sydmon Nguyen-Tran 1N

If you look at this link,
https://lavelle.chem.ucla.edu/wp-conten ... rs_6Ed.pdf
it will show you the errors in the solution manual, and Question 2.93 is one of them.

Sydmon Nguyen-Tran 1N

I'm pretty sure that the solution manual is incorrect for this problem. Based on a few websites as well, they all say that the 3-p orbital has only one radial node, with two nodal planes in total. According to http://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Quantum_Mechanics/09._T...

Sydmon Nguyen-Tran 1N

Yep. Because the molecular formula shows the actual number of atoms of a molecule.

Sydmon Nguyen-Tran 1N

So you're trying to find the volume and you have the moles for Na (for part a) and the molarity. Using stoichiometry, start with 2.15mmol Na divided by the molarity you found (.07967M) and then multiply that by the ratio of moles of Na2CO2 (1 mol) to Na (2 mol), giving you 13.5mL. You repeat this fo...

Sydmon Nguyen-Tran 1N

When calculating molarity, the only information you should need about the solute is the amount of moles of solute you have or need, and this may require you to know how many grams of solute you have depending on what you're given. So no, you do not account for the volume of the solid.

CHEMISTRY COMMUNITY

Search found 21 matches

Re: Intro to O-CHEM CH.1 Problem #28

Re: Priority in Alkenes

Re: (S)-isomer and (R)-isomer

(S)-isomer and (R)-isomer

Re: Third Order Reactions

Re: Quiz 2 preparation #2

Re: Nernst Equation

Re: Higher Entropy

Re: Problem 8.43

Born-Haber Cycle [ENDORSED]

Re: Bond Enthalpy Question Help

Re: Henderson Hasslebach Equation

Re: Keeping Equilibrium with Pressure

Re: 11.7 c

Drawing MO diagrams

Re: MO Diagram

Re: Question 93, Chapter 2 [ENDORSED]

Re: Chapter 2 Homework #15

Re: # of Molecules

Re: G5 [ENDORSED]

Re: Molarity & Volume