Search found 29 matches
- Sun Mar 19, 2017 3:26 am
- Forum: *Cyclohexanes (Chair, Boat, Geometric Isomers)
- Topic: Chair conformations [ENDORSED]
- Replies: 2
- Views: 2603
Re: Chair conformations [ENDORSED]
This is simply due to the orientation of the CH3 substituents as Dr. Lavelle had previously stated that the equitorial position of the methyl makes the structure more stable than the axial position.
- Fri Mar 10, 2017 6:47 am
- Forum: *Alkanes
- Topic: Iso / Neo when to use
- Replies: 3
- Views: 860
Re: Iso / Neo when to use
The actual formula is associated with the prefix iso and neo. For iso it is (CH3)2CH and for neo it is (CH3)3C. For both, I believe it requires that there be at least 5 carbons in order to use. If this criteria is not met, then use systematic naming.
- Tue Mar 07, 2017 7:08 pm
- Forum: *Organic Reaction Mechanisms in General
- Topic: exergonic/exothermic
- Replies: 2
- Views: 808
Re: exergonic/exothermic
I believe exergonic reactions deals with the loss in free energy while exothermic relates to the loss in heat.
- Mon Mar 06, 2017 10:11 pm
- Forum: *Cycloalkanes
- Topic: How much of Common naming do we need to know for Quiz 3?
- Replies: 4
- Views: 1754
Re: How much of Common naming do we need to know for Quiz 3?
In addition to knowing those rules, you should be able to use iso and neo when naming.
- Tue Feb 28, 2017 8:52 pm
- Forum: *Alkanes
- Topic: Naming [ENDORSED]
- Replies: 93
- Views: 16729
Re: Naming [ENDORSED]
What do the numbers represent?
- Wed Feb 22, 2017 9:29 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: HW #17 and #19
- Replies: 2
- Views: 696
Re: HW #17 and #19
Although it is true that we can take any experiment into account, there is a method to choosing which trials to compare. As stated in the course reader, it is important to only have a change in one of the variables while there be no change in molarity of the other substances. This will allow you to ...
- Thu Feb 16, 2017 8:29 pm
- Forum: First Order Reactions
- Topic: First vs. Second Order
- Replies: 6
- Views: 1953
Re: First vs. Second Order
How do you know if it is zero order?
- Thu Feb 09, 2017 3:24 pm
- Forum: Balancing Redox Reactions
- Topic: Balancing Charges?
- Replies: 1
- Views: 543
Re: Balancing Charges?
1. Balance the equation so there are the same number of each element on either side. 2. Pay attention to only the molecules or elements with charges, disregard the other molecules as they will not help in this step. 3. determine the total charge on the left and the total charge on the right. a. of t...
- Thu Feb 09, 2017 3:00 pm
- Forum: Balancing Redox Reactions
- Topic: Basic Solution Redox Reaction
- Replies: 1
- Views: 542
Re: Basic Solution Redox Reaction
I believe we are expected to know both, as basic solutions are a part of the homework problems.
- Sun Feb 05, 2017 7:31 pm
- Forum: Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams
- Topic: Homework 14.13
- Replies: 1
- Views: 502
Re: Homework 14.13
I was having the same issue, I thought that instead of the platinum, the I2 (s) would be in that position because that is the solid.
- Sun Jan 29, 2017 11:00 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: 9.23
- Replies: 1
- Views: 551
Re: 9.23
The molecule with higher entropy is COF2 because as you can recall, Dr. Lavelle specifically talked about the various states a molecule can have. Because BF3 has only the Fluorine element surrounding it, there can be no change in the molecule's structure. COF2 can have different displacement of elem...
- Sat Jan 21, 2017 6:40 am
- Forum: Phase Changes & Related Calculations
- Topic: Q [ENDORSED]
- Replies: 1
- Views: 594
Re: Q [ENDORSED]
There is truly no difference between the two equations. They can be used for any problem, but depending on your preference of units, either equation is reasonable. mcdeltaT is used when the problem include moles for the amount of substance whil ncdeltaT is when the problem states the amount of subst...
- Sat Jan 14, 2017 3:45 am
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: State Functions and Non-State Functions
- Replies: 2
- Views: 645
Re: State Functions and Non-State Functions
As the previous person stated, non-state functions (such as work and energy) do require more information than just the initial and final position. Say there were four people. Two of them went straight to school from their home, while the other two went half way to school, realized they forgot someth...
- Fri Dec 02, 2016 9:02 am
- Forum: *Making Buffers & Calculating Buffer pH (Henderson-Hasselbalch Equation)
- Topic: Homework Question 13.1
- Replies: 2
- Views: 6599
Homework Question 13.1
13.1 Explain what happens to (a) the concentration of H3O+ ions in an aceticacid solution when solid sodium acetate is added; (b) the percentage deprotonation of benzoic acid in benzoic acid solution when hydrochloric acid is added; (c) the pH of the solution when solid ammonium chloride is added to...
- Mon Nov 28, 2016 7:08 am
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 11.07a
- Replies: 1
- Views: 493
Re: 11.07a
For a reaction to be at equilibrium, the amount on either side of the reaction need to be equal. This would mean that the amount of X2 molecules should be proportional to the amount of dissociated x atoms. Within flask 3, there is almost an even number ratio of reactants to product. Flask 4 would no...
- Mon Nov 21, 2016 1:45 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Kp and Kc
- Replies: 4
- Views: 957
Re: Kp and Kc
When writing the expression for Kp, you would write the molecule as a subscript of P to signify that we are using the partial pressures of the molecule to determine the equilibrium constant.
- Fri Nov 18, 2016 10:59 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: 11.89 HW
- Replies: 2
- Views: 682
Re: 11.89 HW
To add on to the previous response,
we know that A is a reactant because the graph shows a decreasing trend
we know that B and C are products because their graphs have an increase in partial pressure.
we know that A is a reactant because the graph shows a decreasing trend
we know that B and C are products because their graphs have an increase in partial pressure.
- Fri Nov 11, 2016 11:35 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Kc or Kp
- Replies: 2
- Views: 563
Re: Kc or Kp
When writing out the expression, when would you have to use partial pressure. For questions within the book, when dealing with gases some had partial pressure while others did not.
- Fri Nov 11, 2016 11:30 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: Textbook 11.31
- Replies: 2
- Views: 696
Re: Textbook 11.31
The solutions manual is not incorrect. The course reader states that when Q<K then there are more reactants present, but this implies that the reaction will continue toward reaching equilibrium. In order for the reaction to reach equilibrium it must create more product.
- Fri Nov 11, 2016 11:25 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: Fall 2016 #6C [ENDORSED]
- Replies: 2
- Views: 771
Re: Fall 2016 #6C [ENDORSED]
I am not sure how you reached the answer larger, but I will explain what I did and maybe you see what differs in our work. 1. Balance the equation I2(g)<-->2I(g) 2. Find the equilibrium constant expression. Kc=[product]/[reactant] = [I]^2/[I2] 3. Plug the known values in. 2.1x10^-3 = [I]^2/ (3.18x10...
- Mon Nov 07, 2016 2:17 pm
- Forum: Hybridization
- Topic: Hybrid Orbitals
- Replies: 4
- Views: 1307
Re: Hybrid Orbitals
One way to conceptually think about hybridization is to think about the energy levels for s and p. When separate, the s orbital has less energy than p, but when they become hybridized it is as though they create a new energy level for them both to exist. When trying to determine what the hybridizati...
- Sun Oct 30, 2016 6:22 pm
- Forum: Limiting Reactant Calculations
- Topic: Percent Yield
- Replies: 3
- Views: 1687
Re: Percent Yield
When solving for a limiting reactant problem that asks for the percent yield of the product these are the steps to follow: 1. convert the moles/grams of the reactants to the moles/ grams of the product that you have to find the percent yield of. Depending on whether the product amount given is in mo...
- Sun Oct 30, 2016 6:10 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Shapes
- Replies: 1
- Views: 427
Re: Shapes
I believe the shape would be bent because the lone pairs surrounding the chlorine atom cause the oxygen atoms to bend at an angle.
- Thu Oct 20, 2016 10:06 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: px,py,pz [ENDORSED]
- Replies: 1
- Views: 490
Re: px,py,pz [ENDORSED]
Both options are accepted but Dr. Lavelle would prefer that we write px, py, pz because it gives more information.
- Thu Oct 20, 2016 10:04 pm
- Forum: Ionic & Covalent Bonds
- Topic: formal charge [ENDORSED]
- Replies: 4
- Views: 2156
Re: formal charge [ENDORSED]
Although I do agree with the post before, I have found that in some cases, getting a 0 Formal Charge is not possible. Sometimes a molecule may be more stable when it is in a -1 or +1 charge simply because this is the same charge for either side. This would mostly be the case for molecules consisting...
- Thu Oct 13, 2016 1:38 pm
- Forum: Bohr Frequency Condition, H-Atom , Atomic Spectroscopy
- Topic: Significant Figures
- Replies: 4
- Views: 1111
Re: Significant Figures
Because the Rydberg constant has 6 significant figures given, this is how many the answer should have as well.
- Fri Oct 07, 2016 7:45 am
- Forum: Limiting Reactant Calculations
- Topic: Finding Molar Mass in a Limiting Reagent Problem [ENDORSED]
- Replies: 3
- Views: 5126
Re: Finding Molar Mass in a Limiting Reagent Problem [ENDORSED]
When dealing with molar mass in L.R. problems, often times the problem will give the mass of the reactants in grams. To find which is the limiting reactant, you have to solve for the mass of the other reactant to see whether or not there was enough of the reactant to begin with. In you example, they...
- Tue Sep 27, 2016 9:51 am
- Forum: Properties of Light
- Topic: Magnetic and Electric fields
- Replies: 4
- Views: 744
Re: Magnetic and Electric fields
Both of them are related to electric charges I believe. So the magnetic field is created around moving electric charges while the electric field is created around any electric charge.
- Tue Sep 27, 2016 9:46 am
- Forum: Student Social/Study Group
- Topic: De Neve Study Group
- Replies: 35
- Views: 4822
Re: De Neve Study Group
I live in Dykstra.