CHEMISTRY COMMUNITY

nikita bhat 2D

This is simply due to the orientation of the CH3 substituents as Dr. Lavelle had previously stated that the equitorial position of the methyl makes the structure more stable than the axial position.

nikita bhat 2D

The actual formula is associated with the prefix iso and neo. For iso it is (CH3)2CH and for neo it is (CH3)3C. For both, I believe it requires that there be at least 5 carbons in order to use. If this criteria is not met, then use systematic naming.

nikita bhat 2D

I believe exergonic reactions deals with the loss in free energy while exothermic relates to the loss in heat.

nikita bhat 2D

In addition to knowing those rules, you should be able to use iso and neo when naming.

nikita bhat 2D

What do the numbers represent?

nikita bhat 2D

Although it is true that we can take any experiment into account, there is a method to choosing which trials to compare. As stated in the course reader, it is important to only have a change in one of the variables while there be no change in molarity of the other substances. This will allow you to ...

nikita bhat 2D

How do you know if it is zero order?

nikita bhat 2D

1. Balance the equation so there are the same number of each element on either side. 2. Pay attention to only the molecules or elements with charges, disregard the other molecules as they will not help in this step. 3. determine the total charge on the left and the total charge on the right. a. of t...

nikita bhat 2D

I believe we are expected to know both, as basic solutions are a part of the homework problems.

nikita bhat 2D

I was having the same issue, I thought that instead of the platinum, the I2 (s) would be in that position because that is the solid.

nikita bhat 2D

The molecule with higher entropy is COF2 because as you can recall, Dr. Lavelle specifically talked about the various states a molecule can have. Because BF3 has only the Fluorine element surrounding it, there can be no change in the molecule's structure. COF2 can have different displacement of elem...

nikita bhat 2D

There is truly no difference between the two equations. They can be used for any problem, but depending on your preference of units, either equation is reasonable. mcdeltaT is used when the problem include moles for the amount of substance whil ncdeltaT is when the problem states the amount of subst...

nikita bhat 2D

As the previous person stated, non-state functions (such as work and energy) do require more information than just the initial and final position. Say there were four people. Two of them went straight to school from their home, while the other two went half way to school, realized they forgot someth...

nikita bhat 2D

13.1 Explain what happens to (a) the concentration of H3O+ ions in an aceticacid solution when solid sodium acetate is added; (b) the percentage deprotonation of benzoic acid in benzoic acid solution when hydrochloric acid is added; (c) the pH of the solution when solid ammonium chloride is added to...

nikita bhat 2D

For a reaction to be at equilibrium, the amount on either side of the reaction need to be equal. This would mean that the amount of X2 molecules should be proportional to the amount of dissociated x atoms. Within flask 3, there is almost an even number ratio of reactants to product. Flask 4 would no...

nikita bhat 2D

When writing the expression for Kp, you would write the molecule as a subscript of P to signify that we are using the partial pressures of the molecule to determine the equilibrium constant.

nikita bhat 2D

To add on to the previous response,
we know that A is a reactant because the graph shows a decreasing trend
we know that B and C are products because their graphs have an increase in partial pressure.

nikita bhat 2D

When writing out the expression, when would you have to use partial pressure. For questions within the book, when dealing with gases some had partial pressure while others did not.

nikita bhat 2D

The solutions manual is not incorrect. The course reader states that when Q<K then there are more reactants present, but this implies that the reaction will continue toward reaching equilibrium. In order for the reaction to reach equilibrium it must create more product.

nikita bhat 2D

I am not sure how you reached the answer larger, but I will explain what I did and maybe you see what differs in our work. 1. Balance the equation I2(g)<-->2I(g) 2. Find the equilibrium constant expression. Kc=[product]/[reactant] = [I]^2/[I2] 3. Plug the known values in. 2.1x10^-3 = [I]^2/ (3.18x10...

nikita bhat 2D

One way to conceptually think about hybridization is to think about the energy levels for s and p. When separate, the s orbital has less energy than p, but when they become hybridized it is as though they create a new energy level for them both to exist. When trying to determine what the hybridizati...

nikita bhat 2D

When solving for a limiting reactant problem that asks for the percent yield of the product these are the steps to follow: 1. convert the moles/grams of the reactants to the moles/ grams of the product that you have to find the percent yield of. Depending on whether the product amount given is in mo...

nikita bhat 2D

I believe the shape would be bent because the lone pairs surrounding the chlorine atom cause the oxygen atoms to bend at an angle.

nikita bhat 2D

Both options are accepted but Dr. Lavelle would prefer that we write px, py, pz because it gives more information.

nikita bhat 2D

Although I do agree with the post before, I have found that in some cases, getting a 0 Formal Charge is not possible. Sometimes a molecule may be more stable when it is in a -1 or +1 charge simply because this is the same charge for either side. This would mostly be the case for molecules consisting...

nikita bhat 2D

Because the Rydberg constant has 6 significant figures given, this is how many the answer should have as well.

nikita bhat 2D

When dealing with molar mass in L.R. problems, often times the problem will give the mass of the reactants in grams. To find which is the limiting reactant, you have to solve for the mass of the other reactant to see whether or not there was enough of the reactant to begin with. In you example, they...

nikita bhat 2D

Both of them are related to electric charges I believe. So the magnetic field is created around moving electric charges while the electric field is created around any electric charge.

nikita bhat 2D

I live in Dykstra.

CHEMISTRY COMMUNITY

Search found 29 matches

Re: Chair conformations [ENDORSED]

Re: Iso / Neo when to use

Re: exergonic/exothermic

Re: How much of Common naming do we need to know for Quiz 3?

Re: Naming [ENDORSED]

Re: HW #17 and #19

Re: First vs. Second Order

Re: Balancing Charges?

Re: Basic Solution Redox Reaction

Re: Homework 14.13

Re: 9.23

Re: Q [ENDORSED]

Re: State Functions and Non-State Functions

Homework Question 13.1

Re: 11.07a

Re: Kp and Kc

Re: 11.89 HW

Re: Kc or Kp

Re: Textbook 11.31

Re: Fall 2016 #6C [ENDORSED]

Re: Hybrid Orbitals

Re: Percent Yield

Re: Shapes

Re: px,py,pz [ENDORSED]

Re: formal charge [ENDORSED]

Re: Significant Figures

Re: Finding Molar Mass in a Limiting Reagent Problem [ENDORSED]

Re: Magnetic and Electric fields

Re: De Neve Study Group