CHEMISTRY COMMUNITY

Kristine_Espinosa_2L

for iso- it's similar to neo- but think of it as only ONE methyl group apart from the continuous chain connected at -chch3

Kristine_Espinosa_2L

Make use of the textbook examples! I used the problems to guide me step by step in doing the problems and worked them until I understood each step. If you have time, read the appropriate sections for each topic and then look at the course reader to summarize what you just read. Reading the topics is...

Kristine_Espinosa_2L

no, isopropyl would indicate that there is only one methyl group away from the chain.
1-isopropyl is pictured here

Kristine_Espinosa_2L

The way to think of neo is that there are 2 methyl groups apart from the main chain at CH3C-

Kristine_Espinosa_2L

Dr. Lavelle, Thank you for being consistently concerned with student learning such as ensuring there were many TA hours and review sessions. No matter the topic, you made sure there was enough help available to assist in understanding good chemistry. Thank you for being an instructor who truly cares...

Kristine_Espinosa_2L

Are you made of Uranium and Iodine?

Because all I can see is U and I ;)

Kristine_Espinosa_2L

Kristine_Espinosa_2L

Q: Anyone know any jokes about sodium?
A: Na

Kristine_Espinosa_2L

For this problem for part c, the answer in the back of the book says 2.85 x 10^12. I'm getting only 2.85 and I'm not sure where the 10^12 comes from. Also for d, the method of solving would just be plugging the appropriate numbers into rate=[A][B^2][C^2], correct?

Kristine_Espinosa_2L

Why did the bear dissolve in water?

It was a polar bear!

Kristine_Espinosa_2L

How many moles are in Guacamole?

Avocado's Number!

Kristine_Espinosa_2L

How often do I make jokes about chemistry?
Periodically.

Kristine_Espinosa_2L

Thank you for this! Helped me comprehend and visualize an atom as well as the concept of it all.

Kristine_Espinosa_2L

I live in Evergreen too! We should get together :-)

Kristine_Espinosa_2L

I believe you mean Å? If so, this is an Angstrom which is used as a unit of measurement for the wavelength of light, it's 10^-10 meter or 0.1 nanometer!

Kristine_Espinosa_2L

I haven't had chem since my sophomore year of high school. My teacher wasn't the best but if you still have contact with them - they are a big help if you require review. The modules are also very helpful and as mention Khan Academy is very helpful, but Crash Course on Youtube is also good for simpl...

CHEMISTRY COMMUNITY

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Homework 15.19 c & d

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