Search found 29 matches
- Wed Mar 15, 2017 5:34 pm
- Forum: Thermodynamic Systems (Open, Closed, Isolated)
- Topic: dU, q, w
- Replies: 3
- Views: 865
Re: dU, q, w
Since U=0, w=-q
- Wed Mar 15, 2017 5:31 pm
- Forum: *Cyclohexanes (Chair, Boat, Geometric Isomers)
- Topic: Q5B on 2008 Final
- Replies: 1
- Views: 434
Re: Q5B on 2008 Final
There is a cis to indicate the placement of the substituents on the chair structure. The cis means that the methyl is axial and the isopropyl is equatorial (or vice-versa).
- Wed Mar 08, 2017 9:17 pm
- Forum: Student Social/Study Group
- Topic: Post All Chemistry Jokes Here
- Replies: 9651
- Views: 3622395
Re: Post All Chemistry Jokes Here
Why do aromatics belong in the nuthouse?
Because they’re all CYCLO.
Because they’re all CYCLO.
- Sat Mar 04, 2017 1:35 pm
- Forum: *Alkanes
- Topic: Order in naming [ENDORSED]
- Replies: 2
- Views: 704
Order in naming [ENDORSED]
For chapter 1 Qs 16 and 17, why are the molecules named:
2-isopropyl-1,1-dimethylcyclopentane in instead of 1,1-dimethyl-2-isopropylcyclopentane
and
4-tertbutyl-1,2-dimethylcyclohexane instead of 1,2-dimethyl-4-tertbutylcyclohexane ?
Thanks!
2-isopropyl-1,1-dimethylcyclopentane in instead of 1,1-dimethyl-2-isopropylcyclopentane
and
4-tertbutyl-1,2-dimethylcyclohexane instead of 1,2-dimethyl-4-tertbutylcyclohexane ?
Thanks!
Re: 1.24
Yes, it appears as if they are ¯\_(ツ)_/¯ Both 2-pentene molecules.
- Wed Mar 01, 2017 2:50 pm
- Forum: *Organic Reaction Mechanisms in General
- Topic: Drawing Reaction Profiles
- Replies: 1
- Views: 539
Re: Drawing Reaction Profiles
Based on what I've seen in examples, as long as you label each step and section of the graph, you can make the graph as high/low/wide as you want. Obviously, you need to have every segment of the graph line up with the right step of the reaction and have them proportional to each other. Hope that he...
- Wed Feb 22, 2017 5:15 pm
- Forum: *Electrophilic Addition
- Topic: intermediate
- Replies: 2
- Views: 639
Re: intermediate
An intermediate is a molecule that is produced from the reactants in the early steps of a mechanism, but is not present in the final molecular formula of the chemical reaction. When you add the mechanism formulas together to get the simplified chemical formula, the intermediates will always cancel.
- Thu Feb 16, 2017 8:31 pm
- Forum: First Order Reactions
- Topic: homework 15.21 and 15.23
- Replies: 1
- Views: 532
Re: homework 15.21 and 15.23
It's negative when you're finding the concentration of a reactant, which is decreasing. It's positive when finding the concentration of the products, which is increasing.
- Sun Feb 12, 2017 3:54 pm
- Forum: Gibbs Free Energy Concepts and Calculations
- Topic: Methods of finding K
- Replies: 1
- Views: 382
Methods of finding K
Can the following equations be used interchangeably to find K?:
deltaG = -RTlnK
deltaEcell = ((RT)/(nF))lnk = (.0257/n)lnK
Thank you!
deltaG = -RTlnK
deltaEcell = ((RT)/(nF))lnk = (.0257/n)lnK
Thank you!
- Mon Feb 06, 2017 9:40 pm
- Forum: Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)
- Topic: Plugging in #s for Q [ENDORSED]
- Replies: 2
- Views: 633
Plugging in #s for Q [ENDORSED]
In the equation E=E - (RT)/(nF) * ln(Q), how do we know which molecules are the products and which are the reactants to plug in for Q? Is it always the cathode, or always the anode, or based off something else entirely?
Thanks
Thanks
- Mon Jan 30, 2017 4:30 pm
- Forum: Phase Changes & Related Calculations
- Topic: Entropy vs Enthalpy
- Replies: 2
- Views: 667
Re: Entropy vs Enthalpy
Entropy (S) is a measurement of disorder and randomness, while enthalpy (H) is the amount of heat a reaction releases or absorbs. Each question will probably specify whether to use entropy or enthalpy, or you can tell from the information the question provides.
- Sun Jan 29, 2017 11:43 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz 1 Preparation Answers
- Replies: 130
- Views: 25684
Re: Quiz 1 Preparation Answers
For #8, I don't understand why the reaction will not be spontaneous at any temperature.
Please help! Thanks!
Please help! Thanks!
- Wed Jan 25, 2017 11:06 pm
- Forum: Entropy Changes Due to Changes in Volume and Temperature
- Topic: Entropy and Stability
- Replies: 1
- Views: 467
Entropy and Stability
Is high entropy more stable than low entropy?
For example, which is more stable: a system with entropy 10 or entropy 20?
For example, which is more stable: a system with entropy 10 or entropy 20?
- Sun Jan 22, 2017 6:16 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Degeneracy and Entropy
- Replies: 1
- Views: 428
Degeneracy and Entropy
In the equation relating degeneracy and entropy, S = kB * ln(W), where do we get the value for kB (k-sub-B)?
- Mon Jan 16, 2017 10:57 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Enthalpy [ENDORSED]
- Replies: 3
- Views: 746
Re: Enthalpy [ENDORSED]
It depends on the elements being used, but in general, you subtract the mean bond enthalpy of the double bond you are forming from the single bond you are breaking. For example, if we take a single bonded C-C and convert it to a C=C bond, we first have to add energy to break the single bond, and the...
- Wed Jan 11, 2017 8:07 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Standard Enthalpy of Formation
- Replies: 1
- Views: 401
Re: Standard Enthalpy of Formation
Heat is an extensive property because it changes when the size of the sample changes. Somethkng that has mass 10 grams will not have the same temperature as something with mass 100 grams.
- Tue Nov 29, 2016 12:40 pm
- Forum: Calculating pH or pOH for Strong & Weak Acids & Bases
- Topic: Identifying a strong acid
- Replies: 6
- Views: 2296
Re: Identifying a strong acid
I don't think that strong and weak acids and bases are determined based on a set number on the pH scale because temperature and solvent change pH. Instead, a strong acid/base is one that completely ionizes in a reaction. A weak acid/base does not completely ionize. You can tell in a question whether...
- Tue Nov 29, 2016 12:32 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Both Roots are positive
- Replies: 2
- Views: 549
Re: Both Roots are positive
One of the roots will be larger than one or both of your concentrations, so when you try subtracting it from your concentration you will get a negative new concentration, which does not make sense. So use the other value that results in two positive concentrations.
- Fri Nov 25, 2016 6:25 pm
- Forum: Identifying Acidic & Basic Salts
- Topic: #12.75
- Replies: 3
- Views: 1686
#12.75
During the analysis of an unknown acid HA, a 0.010 m solution of the sodium salt of the acid was found to have a pH of 10.35. Use Table 12.1 to write the formula of the acid.
I don't clearly understand the answer key, please help.
Thanks!!
I don't clearly understand the answer key, please help.
Thanks!!
- Mon Nov 21, 2016 12:35 am
- Forum: Conjugate Acids & Bases
- Topic: Fundamental J.5
- Replies: 1
- Views: 402
Fundamental J.5
The question reads: Complete the overall equation, and write the complete ionic equation and the net ionic equation for each of the following acid-base reactions. HF (plus) NaOH = LiOH (plus) HI = I understand how to write the overall equations, but I am confused on how to write the complete ionic a...
- Tue Nov 15, 2016 3:00 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Reaction at equilibrium
- Replies: 1
- Views: 495
Reaction at equilibrium
This is a question from the first equilibrium module: For a chemical reaction that has reached equilibrium which statement is false ? a) the forward reaction rate is the same as the reverse reaction rate b) no matter what combination of concentrations of reactants and products we start with the reac...
- Sat Nov 12, 2016 2:21 pm
- Forum: Shape, Structure, Coordination Number, Ligands
- Topic: What is a Ligand?
- Replies: 3
- Views: 1470
Re: What is a Ligand?
A ligand is a molecule or ion that bonds with a metal atom. What we're focusing on is ligands bonding to central transition metals to form coordination compounds. The transition metal itself is typically not the ligand.
- Sat Nov 12, 2016 2:16 pm
- Forum: Naming
- Topic: Subscripts of atoms outside the brackets
- Replies: 1
- Views: 532
Subscripts of atoms outside the brackets
When writing the formula for potassium tetracyanonickelate (II), why is the answer K2[Ni(CN)4] and not just K[Ni(CN)4]?
Thanks.
Thanks.
- Tue Nov 01, 2016 4:12 pm
- Forum: Determining Molecular Shape (VSEPR)
- Topic: Trigonal pyramidal vs. pyramidal
- Replies: 2
- Views: 8154
Trigonal pyramidal vs. pyramidal
Are trigonal pyramidal and pyramidal the same thing? What are the bond angles?
Thanks.
Thanks.
- Tue Oct 25, 2016 3:54 pm
- Forum: Lewis Structures
- Topic: Lewis Structure Octet Rule Exceptions
- Replies: 4
- Views: 954
Re: Lewis Structure Octet Rule Exceptions
H, He, Li, and Be are exceptions since they cannot hold 8 electrons. As for elements that have expanded octets, most of the elements after Si have expanded octets since they're in the third energy level (third row of the periodic table) and have empty d orbitals. I've specifically seen a lot of P an...
- Mon Oct 17, 2016 10:38 pm
- Forum: Electron Configurations for Multi-Electron Atoms
- Topic: Chapter 2 Question 29 [ENDORSED]
- Replies: 3
- Views: 778
Re: Chapter 2 Question 29 [ENDORSED]
I'll go part by part to explain where the numbers come from: a) when l=1, we know it is a p-orbital, and 6 electrons can fit in a p-orbital, so the answer is 6. b) and d) in any m group there are always only 2 electrons maximum. One has upward spin, one has downward. c) when n=2, l can be either 0 o...
- Tue Oct 11, 2016 10:26 pm
- Forum: SI Units, Unit Conversions
- Topic: Quiz 1 number 3
- Replies: 2
- Views: 712
Re: Quiz 1 number 3
You do not need to convert the units. Another way to write Hz is s^-1, so the seconds cancel and you're left with J. The book tends to use s^-1 instead of Hz when giving the units of frequency.
- Tue Oct 04, 2016 5:26 pm
- Forum: Properties of Electrons
- Topic: C-C bond breakage by visible light? [ENDORSED]
- Replies: 1
- Views: 1855
Re: C-C bond breakage by visible light? [ENDORSED]
To answer this you first need to convert the given energy from 348 kJ/mol to J/c-c bond. Basically, multiply by 1000J and divide by 6.022 * 10^23 c-c bonds to get 5.78 * 10^-19 J. Then substitute this energy value into the equation wavelength=hc/E. Your answer ends up being 344 nm, which is in the u...
- Tue Sep 27, 2016 9:22 pm
- Forum: Limiting Reactant Calculations
- Topic: Combustion Analysis
- Replies: 1
- Views: 672
Combustion Analysis
Can someone explain the series of conversions needed to use combustion analysis to find the empirical formula of a molecule given the mass of an unknown compound and the masses of carbon dioxide and water (and any other product) produced? I understand the concept of combustion analysis, but I always...