Search found 32 matches
- Sat Mar 18, 2017 1:23 pm
- Forum: Method of Initial Rates (To Determine n and k)
- Topic: Winter 2016 Q4
- Replies: 1
- Views: 435
Winter 2016 Q4
For this question we are asked to find the rate law and determine the rate constant given a set of data and the reaction: 2ClO (g) + O2 (g) ---> 2ClO2 (g) When we're setting up the rate law, rate= k[ClO]^n * [O2]^m, would we include the coefficient of the ClO? Or is that already accounted for when w...
- Tue Mar 14, 2017 10:12 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Final Exam Details and Review Sessions Winter 2017
- Replies: 114
- Views: 26509
Re: Final Exam Details and Review Sessions Winter 2017
Is the final more geared towards information covered after the midterm? Or will it focus equally on both halves of the quarter? Dr. Lavelle previously replied to a similar question stating that the final will be fairly evenly distributed based on how long each section was covered. "We will spe...
- Wed Mar 08, 2017 8:22 am
- Forum: Biological Examples
- Topic: Lecture Example: Homogeneous Catalyst
- Replies: 1
- Views: 1360
Re: Lecture Example: Homogeneous Catalyst
The overall equation of the reaction would be 1/2(O2) + O2 ---> O3, not looking at the catalysts or intermediates because they appear as both reactants and products and are therefore used up. The catalyst in this case would be NO because it is there from the beginning of the reaction, rather than be...
- Mon Mar 06, 2017 10:10 am
- Forum: *Cycloalkanes
- Topic: Geometric vs Constitutional Isomers [ENDORSED]
- Replies: 2
- Views: 819
Re: Geometric vs Constitutional Isomers [ENDORSED]
To add on, both constitutional isomers and geometric isomers have the same molecular formula. However, constitutional formulas have different connectivity such that they can be drawn differently. Geometric isomers on the other hand have the same connectivity but different arrangements in space which...
- Wed Mar 01, 2017 11:11 pm
- Forum: *Nucleophiles
- Topic: Ambient Nucleophiles
- Replies: 1
- Views: 712
Ambient Nucleophiles
Hi, Even after reading the previous couple posts, I am still confused as to how we would identify the ambient nucleophile. I was wondering if someone could clarify what it is and how we would approach a problem that asks us to identify one. This is problem 4.6 in the OChem textbook: Identify the amb...
Re: Quiz 3
I think it will cover the last half of kinetics, that wasn't covered in Quiz 2, along with the OChem that we've been covering. (Ch. 4 and Ch. 1)
- Wed Feb 22, 2017 11:42 pm
- Forum: Reaction Mechanisms, Reaction Profiles
- Topic: K=...? (pg 73 course reader pre-equilibrium ex)
- Replies: 1
- Views: 516
Re: K=...? (pg 73 course reader pre-equilibrium ex)
Hi! That K would be the equilibrium constant, which would equal to the concentration of the products over the concentration of the reactants. The purpose is to find an equation that relates the intermediate or in this case [N2O2] with [NO]^2. We would do so by treating the first step as if it were a...
- Wed Feb 22, 2017 7:20 pm
- Forum: General Rate Laws
- Topic: 15.13 Homework Question
- Replies: 2
- Views: 793
Re: 15.13 Homework Question
To add on to that, For part a, using the given mass of H2 and I2, you would divide by the molar mass to get the moles of H2 and I2. Then you would calculate the molarity of each using c=m/V. Given the rate constant and the fact that both reactants are first order, we would plug in the concentrations...
- Wed Feb 22, 2017 12:38 am
- Forum: General Science Questions
- Topic: Intro to Organic Chemistry
- Replies: 9
- Views: 1900
Re: Intro to Organic Chemistry
Dr. Lavelle mentioned in another post that we should continue to bring the course reader but the OChem textbook is only for additional readings and assigned problems.
Hope this helps!
Hope this helps!
- Fri Feb 17, 2017 12:15 am
- Forum: Zero Order Reactions
- Topic: Zero Order Half-Life Relationship
- Replies: 1
- Views: 730
Re: Zero Order Half-Life Relationship
Hi! The half life of the reaction is the time it takes for the reaction to reach half the initial concentration. For the case of the zeroth order reaction, the integrated rate law is [A]=-kt + [A]o. Therefore the equation for the half life of this zeroth order reaction would mean the concentration o...
- Mon Feb 13, 2017 4:52 pm
- Forum: Balancing Redox Reactions
- Topic: Balancing 14.5 part d
- Replies: 1
- Views: 589
Re: Balancing 14.5 part d
Hi! I think you might have read the solution manual wrong, but to approach the question, we would split the redox equation into two half equations. P4---> H2PO2- and P4---> PH3 Then to balance in a basic solution, we would first balance out the oxygen atoms then use OH- rather than H+ when balancing...
- Tue Feb 07, 2017 10:53 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Midterm Winter 2017
- Replies: 87
- Views: 20748
Re: Midterm Winter 2017
Will the Feb. 10 review session by Dr. Lavelle be podcasted like last quarter?
- Mon Feb 06, 2017 3:36 pm
- Forum: Balancing Redox Reactions
- Topic: example 14.9
- Replies: 1
- Views: 497
Re: example 14.9
If you break down the redox reaction equation into the half reactions, then you'll get 2Ce^4+ --> 2Ce^3+ On the left hand side, the charge will be 8+, while the right will be 6+. To get a balanced half reaction, you'll have to add 2 moles of e- to the left hand side, which is where the 2 moles in yo...
- Tue Jan 31, 2017 11:16 am
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Ch. 9 #7 HW
- Replies: 1
- Views: 516
Re: Ch. 9 #7 HW
Because there is a temperature change, to calculate the change in entropy, you would use the equation n*Cp*ln(T2/T1) for part (a). n in this case would be 1 mol, while the the Cp would be 5/2*R, which would be 5/2*(8.314 J/K*mol). Lastly, you would convert the temperature to K and take the natural l...
- Tue Jan 31, 2017 11:09 am
- Forum: Thermodynamic Definitions (isochoric/isometric, isothermal, isobaric)
- Topic: work
- Replies: 2
- Views: 545
Re: work
Simply put, the first equation with P*deltaV would be used when there is a constant pressure, whereas the second equation would be used with a variable pressure or when there is an isothermal expansion (no change in temperature and the change in volume is expanding).
- Wed Jan 25, 2017 1:18 pm
- Forum: Concepts & Calculations Using Second Law of Thermodynamics
- Topic: Homework Question 9.15 (a)
- Replies: 1
- Views: 645
Homework Question 9.15 (a)
Question: Use data in Table 8.3 or Appendix 2A to calculate the entropy change for (a) the freezing of 1.00 mol H2O(l) at 0.00 C
I was wondering how I should approach this. Thanks in advance!
I was wondering how I should approach this. Thanks in advance!
- Thu Jan 19, 2017 10:34 am
- Forum: Heat Capacities, Calorimeters & Calorimetry Calculations
- Topic: Problem Three Part A
- Replies: 1
- Views: 491
Re: Problem Three Part A
Work is equal to -P multiplied by the change in volume. The equation for volume is area of the base times the height. In this case the distance that the pump has moved would equal to the height, therefore the work would equal to -P*A*d. However, because the units are given in cm, we would convert to...
- Mon Jan 16, 2017 3:31 pm
- Forum: Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)
- Topic: Homework 8.59
- Replies: 2
- Views: 583
Re: Homework 8.59
You are correct by calculating the standard enthalpy of formation of the products and subtracting the standard enthalpy of formation of the reactants. However, as we went over in class, the standard enthalpy of formation of an element in its most stable form is zero. In this case, the most stable fo...
- Wed Jan 11, 2017 8:43 pm
- Forum: Administrative Questions and Class Announcements
- Topic: Quiz Practice
- Replies: 5
- Views: 950
Re: Quiz Practice
The booklet of practice midterms and finals was offered for an additional charge at the store, however the end of the course reader also has some practice exams.
- Sat Dec 03, 2016 10:38 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: 2007 Final Question 5B
- Replies: 2
- Views: 646
Re: 2007 Final Question 5B
No, Kp was given. The solution includes Q to find the direction in which the reaction proceeds. However because the question doesn't explicitly state to solve for Q, I was wondering if it was necessary.
- Sat Dec 03, 2016 10:26 pm
- Forum: Non-Equilibrium Conditions & The Reaction Quotient
- Topic: 2007 Final Question 5B
- Replies: 2
- Views: 646
2007 Final Question 5B
Given: N2O4 (g) \rightleftharpoons NO2 (g) What are the equilibrium partial pressures of N2O4 and NO2 when 0.20 mol of N2O4 and 0.80 mol of NO2 are sealed in a 2.00 L container at 100 degrees Celsius. When the reaction reaches equilibrium at 100 degrees Celsius, Kp= 11.0. The solution in the book ca...
- Tue Nov 29, 2016 4:23 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Drawing Molecular Orbital Diagrams
- Replies: 1
- Views: 620
Drawing Molecular Orbital Diagrams
Hi,
When drawing molecular orbital diagrams, I was wondering when and why the molecular orbital would be below the atomic orbital? Thanks!
When drawing molecular orbital diagrams, I was wondering when and why the molecular orbital would be below the atomic orbital? Thanks!
- Mon Nov 21, 2016 9:17 am
- Forum: Administrative Questions and Class Announcements
- Topic: Bruincast
- Replies: 26
- Views: 10516
Re: Bruincast
The podcasts (audio) definitely work for iPad and iPhone, but I haven't tried out the Webcasts yet.
- Tue Nov 15, 2016 5:33 pm
- Forum: Equilibrium Constants & Calculating Concentrations
- Topic: Quiz 3 Prep Fall 2014 #10
- Replies: 2
- Views: 733
Quiz 3 Prep Fall 2014 #10
For the following reaction, if initially 0.100 mol of H2O (g) is placed in a 4.0 L vessel, what is the equilibrium partial pressures of each reactant and of each product? H2O (g) + C(s) <-> H2 (g) + CO (g) Kp = 3.72 at 1000 K For the question stated above, I found the molarity for H 2 O, 0.025 M, an...
- Sun Nov 13, 2016 12:04 am
- Forum: Naming
- Topic: Naming CN-
- Replies: 1
- Views: 425
Naming CN-
Hi,
I was wondering if there was a difference between cyanido and cyano? The book uses cyanido while the course reader uses cyano. Would it be wrong if we used one instead of the other? Thanks!
I was wondering if there was a difference between cyanido and cyano? The book uses cyanido while the course reader uses cyano. Would it be wrong if we used one instead of the other? Thanks!
- Sun Nov 06, 2016 9:44 pm
- Forum: Naming
- Topic: Number 29 from the Hw [ENDORSED]
- Replies: 4
- Views: 780
Re: Number 29 from the Hw [ENDORSED]
Hi,
I was wondering how you would go about finding the oxidation numbers for more complicated compounds, such as [Co(CN)5(OH)2)]2- ? Thanks!
I was wondering how you would go about finding the oxidation numbers for more complicated compounds, such as [Co(CN)5(OH)2)]2- ? Thanks!
- Sun Nov 06, 2016 1:37 pm
- Forum: *Molecular Orbital Theory (Bond Order, Diamagnetism, Paramagnetism)
- Topic: Anti bonding Orbitals
- Replies: 3
- Views: 808
Re: Anti bonding Orbitals
Hi,
I was wondering when you would know to draw the sigma 2p orbital above the pi 2p orbital or below it for the molecular orbital energy-level diagram?
Thanks!
I was wondering when you would know to draw the sigma 2p orbital above the pi 2p orbital or below it for the molecular orbital energy-level diagram?
Thanks!
- Fri Oct 28, 2016 1:01 am
- Forum: Bond Lengths & Energies
- Topic: Arranging Ions According to Bond Length
- Replies: 1
- Views: 639
Arranging Ions According to Bond Length
Hi,
I was wondering, for questions that ask you to arrange the ions according to bond length, is it necessary to draw out the Lewis Dot Structure (to find out whether it is single, double, or triple bond and compare)? Or is there another method?
Thanks!
I was wondering, for questions that ask you to arrange the ions according to bond length, is it necessary to draw out the Lewis Dot Structure (to find out whether it is single, double, or triple bond and compare)? Or is there another method?
Thanks!
- Fri Oct 21, 2016 10:19 pm
- Forum: Sigma & Pi Bonds
- Topic: Sigma and Pi Bonds for Quiz 2
- Replies: 3
- Views: 1088
Re: Sigma and Pi Bonds for Quiz 2
Hi,
Does anyone happen to know how to go about solving these problems though? What do the sigma and pi bonds mean in terms of the bonds? Thanks!
Does anyone happen to know how to go about solving these problems though? What do the sigma and pi bonds mean in terms of the bonds? Thanks!
- Wed Oct 12, 2016 9:18 am
- Forum: Empirical & Molecular Formulas
- Topic: Fall 2015 Quiz Prep question #5 [ENDORSED]
- Replies: 3
- Views: 981
Re: Fall 2015 Quiz Prep question #5 [ENDORSED]
Hi,
Regarding the ratio, I got 1:4.5:1 for C, H, and O respectively. However, I was wondering how you would know to round down to 4 for H instead of multiplying the entire thing by 2 to get a whole number for H? Thanks!
Regarding the ratio, I got 1:4.5:1 for C, H, and O respectively. However, I was wondering how you would know to round down to 4 for H instead of multiplying the entire thing by 2 to get a whole number for H? Thanks!
- Sun Oct 09, 2016 11:20 am
- Forum: *Shrodinger Equation
- Topic: Expansion of Shrodinger Equation [ENDORSED]
- Replies: 3
- Views: 847
Expansion of Shrodinger Equation [ENDORSED]
Hi,
I was reading through Chapter 1 and saw that the book included an expanded version of the Schrodinger equation ( ). I was wondering what this meant and if we needed to know it for quizzes or exams?
Thanks!
I was reading through Chapter 1 and saw that the book included an expanded version of the Schrodinger equation ( ). I was wondering what this meant and if we needed to know it for quizzes or exams?
Thanks!
- Sat Oct 01, 2016 11:59 pm
- Forum: Photoelectric Effect
- Topic: 1:1:1 ratio
- Replies: 2
- Views: 443
Re: 1:1:1 ratio
For the first part of the question regarding the photoelectric effect, I believe when the energy of the photon is greater than or equal to the energy binding together the specific atom and the electron, then one photon will interact with one atom to eject one electron.