CHEMISTRY COMMUNITY

Hao 1I

Noting that the y-axis is the potential energy, step 1 requires the most potential energy. Therefore it has the highest activation energy. The difference between TS 1 and the initial value has a greater energy barrier compared to the difference between TS 2 and the local energy minimum.

Hao 1I

The steric factor, denoted as P, takes into account the relative orientation of the molecules. Molecules have to be oriented in a certain way in order for the collision to break / form the bonds. The steric factor is used to calculate the rate constant, k, where k = (steric factor, P) x (collision f...

Hao 1I

Also consider the phase changes from reactants to products.

Hao 1I

The larger the k value, the faster the rate of the reaction. Consider, Rate = k [A] for first order reactions.

Hao 1I

The equation, [A]=[A]0/1+[A]0*kt, is a second order integrated rate law and was used to derive its half life, which is t,(1/2) = 1 / (k[A]0). The second order integrated rate law was derived from the rate law, RATE = k[A]^2.

Hao 1I

Gold will not dissolve when delta G is positive because it will be a non-spontaneous process.

Hao 1I

You would use Nernst Equation when the reaction is not at standard conditions and not at equilibrium.

Hao 1I

If you reverse the cell diagram, say from Cathode||Anode and that for the cathode and anode, Products|Reactants, then you have to change the sign of cell potential.

Hao 1I

A comma represents the reactant and product that are in the same phase whereas a vertical line means they are in different phases.

Hao 1I

The process for writing a cell diagram is typically arranged, Anode||Cathode where || represents the salt bridge, | represents a change in phase, and a comma represents the same phase. Inert metallic component of an electrode is written on the outside of the cell diagram. Also, Reactant|Product for ...

Hao 1I

The standard reduction potential is an intensive property. Think of this mathematically. If you rearrange the equation to E = -(delta G) / nF, the value of G changes as n changes too so E stays the same.

Hao 1I

The temperature is 111K because that is the boiling point for CH4. The equation for change in entropy for vaporization is equal to the enthalpy of vaporization divided by the boiling point temperature ( delta S = delta H of vaporization / Temp. at boiling point ).

Hao 1I

Why is the heat capacity of lead greater than that of diamond?

Hao 1I

The second equation is halved because we want to find the enthalpy of one mole of dinitrogen pentaoxide.

Hao 1I

Students fear O-chem so much because they go through alkynes of trouble.

Hao 1I

Because the glucose solution is considered very dilute, the change in solvent concentration due to water would be so insignificant that it can be ignored.

Hao 1I

It is divided by 100 because the graph is given in kPa. You have to convert kPa to bar. 1 kPa equals 0.01 bar.

Hao 1I

Start with the ICE chart and and convert the grams of CO2 to moles. Then knowing that there are 2 moles of NH3 for every one mole of CO2, moles of CO2 will be doubled for NH3. Be aware that NH4(NH2CO2) is a solid!

Hao 1I

The question asks you to refer to the chart from Table 11.2

Hao 1I

Subtracting 17.4g of CO2 from 25.0g of ammonium carbonate does not work. 25.0g of ammonium carbonate is present initially (before any reaction happened) but only 17.4g CO2 are present in equilibrium . Because 17.4g of CO2 are present in equilibrium, there are still still some amount of ammonium carb...

Hao 1I

The molecular orbital diagram is based on the atom's atomic number, not the number of their valence electrons. Therefore for atoms Z<8, the order should be pi then sigma, and for atoms Z greater than or equal 8, the order would be sigma the pi.

Hao 1I

They are both technically the same, except that the structure on the right is more specific because the right represents the see-saw shape according to the VSEPR Model

Hao 1I

The difference in electronegativity is also described as the average of the ionization energy and the electron affinity. Therefore the higher the ionization energy, the larger electronegativity difference is and hence, the more electronegative, the more ionic the bond is. The strength of the bond is...

Hao 1I

First, you need to convert 2.93 eV to joules because work function should be in joules. 1eV is 1.602x10^-19 J.
And to set this up, you need to compare which laser provides the most energy.

Hao 1I

You have to divide the total volume again because the equation is M (initial) x V (initial) = M (final) x V (final), where the diluted solution is the final phase.

Hao 1I

A) To find the limiting reagant for the formation of P4O10, you would use stoichiometry to compare the usage of oxygen by P4 in both reactions. Given that 5.77g of oxygen is in the vessel, determine if there is enough oxygen present for the following reaction. B) Knowing that you have 5.77g of oxyge...

CHEMISTRY COMMUNITY

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Re: Self test 4.4A

Re: Boltzmann Distribution and Arrhenius Equation

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Heat Capacity: Lead vs. Diamond

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