## Search found 105 matches

Sun Oct 06, 2019 6:11 pm
Forum: Balancing Chemical Reactions
Topic: Question H17
Replies: 1
Views: 48

### Question H17

Steps into solving H17.
Write a balanced equation for the complete combustion (reaction with oxygen gas) of liquid heptane , C7H16 a component typical of the hydrocarbons in gasoline to carbon dioxide gas and water vapor
Sun Oct 06, 2019 6:05 pm
Forum: Molarity, Solutions, Dilutions
Topic: Question G7
Replies: 2
Views: 43

### Re: Question G7

1. Find out how much grams of KNO3 are in the 510 gram sample 2. Divide the 5.45% by 100 to get .0545 3. Multiply .0545g (percent of KNO3) by 510g to determine the amount of KNO3in solution which equals 27.8g 4. Take the total amount of 510g and subtract by 27.8 to find out how much of the aqueous s...
Sun Oct 06, 2019 6:02 pm
Forum: Molarity, Solutions, Dilutions
Topic: G. 13
Replies: 5
Views: 124

### Re: G. 13

Dilution Formula: M1V1=M2V2
Therefore, (0.20NH4No3)(1.0L)=M2(4.0L) - you add the 3.0L and 1.0L
=.05 mol NH4NO3
Sun Oct 06, 2019 5:59 pm
Forum: Molarity, Solutions, Dilutions
Topic: G5
Replies: 6
Views: 207

### Re: G5

-1st step involves calculating the moles of Na2CO3

2.111gNa2CO3
_____________________ = .01992 mol NaCo3
105.991 g/mol Na2CO3

-2nd step
.01992 mol/.250L=.0769 mol/L or about .080mol/L

(a) Convert mmol to mol .002015 mol Na/0.16 mol/L = 0.013 L Na x 1000ml = 13 mL Na is needed to transfer
Sun Oct 06, 2019 5:44 pm
Forum: Molarity, Solutions, Dilutions
Topic: Volumetric Analysis
Replies: 2
Views: 63

### Volumetric Analysis

L37) Part b: How many milliliters of 0.20M NaOH(aq) could be neutralized by 100.mL of the diluted solution?