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### Quiz 1, Preparation 2, Q1

Posted: Fri Sep 30, 2016 12:52 am
Hi! For this question
"How many grams of NaOH do you need to prepare a 3.0 x 10^2 mL stock solution of 2.00 M NaOH?
How does the set up begin for this?

### Re: Quiz 1, Preparation 2, Q1

Posted: Fri Sep 30, 2016 1:26 am
Hi Ashley!

To set up this problem you want to use the Molarity equation: $\mathit{M} = \frac{\mathit{n}}{V}$ (Molarity = moles of solute/Liters of solution).

We are given the Molarity (2 M NaOH) and the volume (.3 L) and we must solve for the moles of solute (NaOH). $\mathit{2 M} = \frac{\mathit{n}}{.3 L}$

Once we get our n, moles of NaOH, we can then find out how many grams we need by multiplying the moles by the molar mass of NaOH (39.997 g/mol NaOH).

Hope this helps!