Quiz Prep: Fall 2014 #4  [ENDORSED]

Moderators: Chem_Mod, Chem_Admin

Taylor_Yamane_2L
Posts: 23
Joined: Wed Sep 21, 2016 3:00 pm
Been upvoted: 1 time

Quiz Prep: Fall 2014 #4

Postby Taylor_Yamane_2L » Sun Oct 09, 2016 2:41 pm

This problem seems fairly simple but I can't seem to get the right answer, wondering if anyone can help me out. Thanks!

"Calculate the volume of 0.642 M KOH (aq) that should be used to make 1.00 L of 0.101 M KOH (aq)."

emilie liu 3G
Posts: 23
Joined: Fri Jul 22, 2016 3:00 am

Re: Quiz Prep: Fall 2014 #4  [ENDORSED]

Postby emilie liu 3G » Sun Oct 09, 2016 2:50 pm

Use the equation for dilutions: M1V1=M2V2
When substituting values you should get (.642M)(xL)=(1.00L)(0.101M)
Solve for xL

Taylor_Yamane_2L
Posts: 23
Joined: Wed Sep 21, 2016 3:00 pm
Been upvoted: 1 time

Re: Quiz Prep: Fall 2014 #4

Postby Taylor_Yamane_2L » Sun Oct 09, 2016 4:32 pm

oh I see my mistake now, thanks so much for your help!!


Return to “Molarity, Solutions, Dilutions”

Who is online

Users browsing this forum: No registered users and 1 guest