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Help needed for molarity problem

Posted: Fri Oct 14, 2016 8:15 pm
by Jaipaul_Bhangu_3H
Hello, I am not sure how to approach this problem. Can someone please help me?

Re: Help needed for molarity problem  [ENDORSED]

Posted: Fri Oct 14, 2016 8:52 pm
by Yamilex Velgara 2I
In order to solve this problem, you will be using MV=MV. You are given the initial mass of the solute, the initial volume, the final volume, and you are asked to find the final molarity. The molar mass of KCl is 74.551 g/mol (found using the molar masses of K and Cl). First, find the initial molarity of the solution:

M initial = 55.1g KCl x ((1mol KCl)/(74.551 g KCl)) x (1/.075 L) = 9.85455147 mol/L

This allows you to cancel out grams, and you are left with mol/L.

Next, rearrange the formula MV=MV to solve for M final. You will get M = MV/V. Plug in and solve:

M final = ((9.85455147 mol/L)(.075 L))/(.125 L) = 5.912730882 mol/L = 5.91 mol/L --- use 3 sig figs because that was given initially.