Why amount of CH3CO2- doubled for each Ca(CH3CO2)2

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Chem_Mod
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Why amount of CH3CO2- doubled for each Ca(CH3CO2)2

Postby Chem_Mod » Fri Oct 21, 2011 6:23 pm

Question: When trying to determine the concentration of CH3CO2- from Ca(CH3CO2)2, why is the amount doubled?

Chem_Mod
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Re: Why is there double CH3CO2- for each Ca(CH3CO2)2

Postby Chem_Mod » Fri Oct 21, 2011 6:23 pm

Answer: The concentration is doubled because your initial molecule is Ca(CH3CO2)2, which has 2 moles of (CH3CO2) per 1 mole of the molecule. That is why the molecular formula is written as it is.

Carolyn Stephens 3H
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Re: Why amount of CH3CO2- doubled for each Ca(CH3CO2)2

Postby Carolyn Stephens 3H » Fri Oct 02, 2015 4:01 pm

If you think about the definition of a mole, one mole of Ca(CH3CO2)2 has 6.022x10^23 molecules, but each molecule has one mole of Ca and 2 moles of CH3CO2- (so, 2x6.022x10^23)and therefore every time you relate the 2 (Ca(CH3CO2)2 and CH3CO2-) you would need to double the amount of moles to make it consistent. I hope this makes sense(:

Yixiao Hu 3C
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Re: Why amount of CH3CO2- doubled for each Ca(CH3CO2)2

Postby Yixiao Hu 3C » Sun Oct 07, 2018 11:07 pm

Cause if you wanna have Ca(CH3CO2)2, you have to have one Ca+ and two (CH3CO2) at the same time. so when you are going to calculate the concentration of ca(ch3co2)2, the concentration of ch3co2- must be two times of that of ca+

Kristy 1F
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Re: Why amount of CH3CO2- doubled for each Ca(CH3CO2)2

Postby Kristy 1F » Wed Oct 10, 2018 12:39 am

Since each Ca2+ combine with 2 (CH3CO2)-


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