L39  [ENDORSED]

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sofiakavanaugh
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L39

Postby sofiakavanaugh » Mon Oct 09, 2017 12:15 am

A 1.50 g sample of metallic tin was placed in a 26.45 g crucible and heated until all the tin had reacted with the oxygen in air to form an oxide. The crucible and product together were found to weigh 28.35g. What is the empirical formula of the oxide? Write the name of the oxide.

Could someone please tell me the steps they took to complete this question?

Jade Fosburgh Discussion 2C
Posts: 59
Joined: Fri Sep 29, 2017 7:07 am

Re: L39  [ENDORSED]

Postby Jade Fosburgh Discussion 2C » Mon Oct 09, 2017 12:34 am

28.25-26.45=1.90g

a) convert 1.50 g of Sn to moles --> 1.264*10-2 mol Sn
b) convert .40 g of O to moles --> 0.025 mol O

Divide both moles of O and Sn by 1.264*10-2 to get empirical formula

SnO2 (Tin Oxide)


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