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Postby nelms6678 » Sat Dec 09, 2017 3:08 pm

Practice Problem

How many grams of NaOH do you need to prepare a 3.00x10^2 mL stock solution of 2.00M NaOH?
---> 24.0g

So in the next set: How many milliliters of the stock solution would you need to make a 250 mL of 0.650M NaOH solution?
how would you do this problem?

Kevin Liu 3G
Posts: 28
Joined: Fri Sep 29, 2017 7:07 am

Re: Solutions

Postby Kevin Liu 3G » Sat Dec 09, 2017 3:49 pm

It should be .0024 grams of NaOH because molarity is moles/liters. The solution is given in milliliters so you have to convert that to liters.

To solve for the part you're asking about, you do MV (initial) = MV (final)
That means (2)(V) = (.250)(.650)
Then you solve for V to know how much stock solution you need.

Hopefully that helps.

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