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G 13

Postby nikitasridhar_1b » Tue Apr 10, 2018 1:36 am

I got the concentration of the diluted solution as 0.05M, and so shouldn't the number of mols of the compound when the volume is 0.1L be 0.2? not sure why the answer is 0.01

Kuldeep Gill 1H
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Re: G 13  [ENDORSED]

Postby Kuldeep Gill 1H » Tue Apr 10, 2018 7:35 am

Hi for G13 you take the dilution equation and setting it up it would be 1*.20=4*M. Solve for M and that you give you the concentration of the diluted solution which would be as you said .05M but then it says you took 100mL of the DILUTED solution and fed it to each plant so for this you would set the concentration(.05M) equal to x/.1L
(Converted mL to L) so your setup should be .05=moles/.1L solve for moles which will get you .005 moles but in the formula you will notice there are 2 N so multiply that by 2 and you get .01...... hope that helps!

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