Mixtures and Solutions

Moderators: Chem_Mod, Chem_Admin

204929947
Posts: 76
Joined: Fri Apr 06, 2018 11:03 am

Mixtures and Solutions

Postby 204929947 » Tue Apr 10, 2018 3:21 pm

I am a bit confused on how to use the equations provided by section G.
Can someone please explain what "c=n/V" and "n=m/M"?
Also, 1 M = 1 mol*L^-1, im a bit confused on what this means and how to use it in the formulas above.

Toru Fiberesima 1L
Posts: 63
Joined: Fri Apr 06, 2018 11:02 am

Re: Mixtures and Solutions

Postby Toru Fiberesima 1L » Tue Apr 10, 2018 4:37 pm

Hi so n is moles, m is mass and M is molar mass. Thus, moles is equal to mass divided by molar mass. You would get the molar mass from the periodic table. Also, c is concentration, n (again) is moles and V is volume.Thus, concentration is equal to moles divided by volume of solution. In each equation, knowing 2 values will let you calculate the other.

As M is Molarity aka concentration when concerning solutions, 1M is equal to moles/volume= 1 mol*L^-1

Yixiao Hu 3C
Posts: 45
Joined: Fri Sep 28, 2018 12:19 am

Re: Mixtures and Solutions

Postby Yixiao Hu 3C » Sun Oct 07, 2018 11:12 pm

c is the concentration of solution, while n equals the mole of the matter and v equals the volume the solution.It's better to understand in this way, if you wanna know how matter is concentrated in the solution in the units of mole, you should divide the total amount of matter( in the unit of mole0) with the total volume. and that works the same for the equation"n=m/M"


Return to “Molarity, Solutions, Dilutions”

Who is online

Users browsing this forum: No registered users and 1 guest