Fundamentals HW G.13

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DomMaiorca_1I
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Fundamentals HW G.13

Postby DomMaiorca_1I » Tue Apr 10, 2018 7:44 pm

G.13 To prepare a fertilizer solution, a florist dilutes 1.0L of 0.20M NH4NO3 (aq) by adding 3.0L of water. The florist then adds 100. mL of the diluted solution to each plant. How many moles of nitrogen atoms will each plant receive?

I first used M1V1 = M2V2 to find the concentration of diluted NH4NO3 to be 0.050 M, however I'm confused where to go from here.

Thanks in advance!

Patience Olsen 1A
Posts: 28
Joined: Fri Apr 06, 2018 11:04 am

Re: Fundamentals HW G.13

Postby Patience Olsen 1A » Wed Apr 11, 2018 1:07 pm

Find the moles of NH4NO3 in each 100. mL sample:
0.050 mol NH4NO3/L * 0.100 L = 0.0050 mol NH4NO3

In each molecule of NH4NO3, there are 2 nitrogen atoms. Multiply by this ratio to find the moles of nitrogen:
0.0050 mol NH4NO3 * 2 mol N/1 mol NH4NO3 = 0.0100 mol N

Each plant receives 0.0100 mol N.


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