Homework Problem G17

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Sarai Ventura 1L
Posts: 30
Joined: Mon Apr 09, 2018 1:39 pm

Homework Problem G17

Postby Sarai Ventura 1L » Wed Apr 11, 2018 9:03 am

(a)Determine the mass of anhydrous copper(II) sulfate that must be used to prepare 250mL of 0.20M CuSO4 (aq). (b) Determine the mass of CuSO4x5H20 that must be used to prepare 250mL of 0.20 M CuSO4(aq).

DomMaiorca_1I
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Joined: Fri Apr 06, 2018 11:03 am
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Re: Homework Problem G17

Postby DomMaiorca_1I » Wed Apr 11, 2018 12:11 pm

This is similar to example G.2. For both a and b, since volume and molarity are given, you just multiply those quantities by the molar mass. (see formulas n = cV and m = nM)

First, remember to convert 250 mL to 0.250L

a) molar mass CuSO4 = 159.60 g/mol -1
mass of CuSO4 = (0.20mol/L -1) x (0.250L) x (159.60 g/mol -1) = 8.0 g

b) molar mass CuSO4x5H2O = 249.68 g/mol -1
mass of CuSO4x5H2O = (0.20mol/L -1) x (0.250L) x (249.68 g/mol -1) = 12.0 g

DomMaiorca_1I
Posts: 31
Joined: Fri Apr 06, 2018 11:03 am
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Re: Homework Problem G17

Postby DomMaiorca_1I » Wed Apr 11, 2018 12:14 pm

Also, sorry if the -1's throw you off, the superscript button wasn't working correctly, but they're just there for unit notation.


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