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I believe you would have to convert the molarity of both substances into moles, then add together the two substance's moles. Add together the liters, then divide the new moles by the new amount of liters to get the new molarity.
In dilutions, the value of n, the moles of solute, ALWAYS remains the same. That is why N(initial) = N(final). And thus, M(i)V(i) = M(f)V(f). V(f) also, is the value of the initial solution PLUS the additional solution required for diluting.
Another note on this topic - I asked my TA what happens when you remove a solute and if that changes the volume. She said that typically the change in volume would be so small we're not expected to calculate the density and correspodning change in volume. However, this calculation density = (mass)/(volume) might be handy to know just in case.
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