Test #1 Question 1 part B

Nabeeha Khan 1D
Posts: 30
Joined: Fri Apr 06, 2018 11:03 am

Test #1 Question 1 part B

QUESTION1:

A) A solution of sodium carbonate is prepared by dissolving 4g of salt to 1L water. What is the concentration of sodium ions for the above solution?

B) The above solution is diluted with 1L of 0.200 M sodium chloride solution. What is the concentration of sodium ions after the dilution?

So for part A of the question, I know that the answer is 0.0755 M of sodium ions. I understand how to do part A but I'm not sure how to even start part B. Can someone explain how to do part B and give what the correct answer would be?

Alesha Vaughn 1E
Posts: 18
Joined: Fri Apr 06, 2018 11:05 am

Re: Test #1 Question 1 part B

You would take the mols of the sodium ions and divide it by the total volume. And the mols of the sodium ions include the mols of sodium ions from the sodium carbonate and the mols from the sodium chloride. The total volue would be 2.00 L because it was first dissolved in 1L of water and the 1L of sodium chloride solution. So (1.00L)(0.0755M) + (1.00L)(0.200M)/ 2.00L = 0.137