Molarity and Dilution of a Solution:Post-Module Assessment Question 19

[Helen Mejia 1I]

Hi, I am having trouble with question 19 from the molarity post-assessment. The question says, calculate the volume of a 0.06 M sodium chloride solution containing 0.03 moles of sodium chloride.

What I did to solve this was using the molarity formula.
Molarity (M)= moles (n)/ volume(v).
since it was asking for the volume, I used: Volume (v)= Molarity/moles -> V= .06/.03, and like that I got 2 Liters. But my answer was wrong.
Please help! thank you (:

[Reva Kakaria 1J]

Hi! When I solve for V using the formula M = n/V, I get V = n/M, so I think you might have accidentally inverted molarity and moles. Then when I do the problem, I get
V = 0.03/0.06, which gives me 0.5 Liters.
I hope this helps!

[Helen Mejia 1I]

Thank you! I see the mistake I did! I think the answer you got is correct since it was one of the options! (: