E3 (sixth edition

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Chloe Orsini 1K
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Joined: Fri Sep 28, 2018 12:18 am

E3 (sixth edition

Postby Chloe Orsini 1K » Tue Oct 02, 2018 1:40 pm

For this problem it asks you to balance to sides of a scale for two types of atoms of different molar masses. On each side in the image are 9 circles, im assuming representing the atoms. For this problem do we assume there are 9 gallium atoms and then use the molar masses to find the number of astatine atoms(and assume there are 9 but that we need to add to this 9 to balance the scale?)

AustinGrove3B
Posts: 53
Joined: Fri Sep 28, 2018 12:23 am

Re: E3 (sixth edition

Postby AustinGrove3B » Tue Oct 02, 2018 2:00 pm

You are correct that there are 9 Gallium molecules on the left. You do not know how many Astatine molecules you need to balance it. The simple way to do it is 210g mol / 70g mol =3. So each Astatine molecule will be 3 times as massive as each Gallium atom. Since there are 9 Gallium atoms, 3 Astatine atoms should balance the scale (3 total astatine on the right..not in addition to the ones in photo).


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