Question M9

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Alexis Webb 2B
Posts: 124
Joined: Thu Jul 11, 2019 12:15 am

Question M9

Postby Alexis Webb 2B » Tue Oct 01, 2019 8:38 pm

The question states, “Copper (II) nitrate reacts with sodium hydroxide to produce a precipitate of light blue copper (II) hydroxide. Write the net ionic equation for the reaction.” I’m not sure why the answer is Cu2+ + 2OH —> Cu(OH)2. Why is there no Na in the equation?

SnehinRajkumar1L
Posts: 101
Joined: Thu Jul 11, 2019 12:15 am

Re: Question M9

Postby SnehinRajkumar1L » Tue Oct 01, 2019 8:58 pm

Net ionic equations only show the reactants that participate in the reaction. Since the reaction produces a copper hydroxide, the only reactants that matter are the copper and hydroxide. The sodium dissociates in the solution and does not contribute to the precipitate.


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