Volume formulas
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Volume formulas
What is the difference in using the two formulas for calculating the volume of a solution: V = n/c and V(initial) = [C(final)V(final)]/C(initial)? When is it appropriate to use either formula?
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Re: Volume formulas
It depends on what the questions has given you and what it's asking for. The first one is generally used if you are trying to convert between moles and molarity given the volume. The second one is mostly used for dilution where you transfer different volumes from one concentration to another.
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Re: Volume formulas
The first is usually used to find the molarity of a solution when the moles of solute (n) and the volume of solution (v) are given. The formula can also be rearranged to find moles or volume if the other two values are given. The second formula is used when dilution is occurring (adding more solvent to decrease concentration). You can use it to find the molarity or volume of the initial or final/concentrated or diluted solution using the equation.
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Re: Volume formulas
In the formulas discussed above, what does the C mean? V = n/c and V(initial) = [C(final)V(final)]/C(initial)
Do the lower case c and upper case C represent the same thing?
Do the lower case c and upper case C represent the same thing?
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Re: Volume formulas
Kristina Rizo 3K wrote:In the formulas discussed above, what does the C mean? V = n/c and V(initial) = [C(final)V(final)]/C(initial)
Do the lower case c and upper case C represent the same thing?
I apologize for the notation there. Yeah the lower case and upper care represent the same thing, concentration.
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Re: Volume formulas
I am also confused about this... on page F57 of the textbook in the box called G1 there is a description on how to calculate the volume of stock solution required for a given dilution... it seems like v = n/c is used when you have/ have found the amount of solute in the final solution and want to find the initial volume of the initial (not diluted) solution. However I'm not sure.
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Re: Volume formulas
For me the most straightforward way is to use the equation m1v1=m2v2 then plug in molarities and volumes to find the unknown. I believe this equation (or alternate versions of this) should be all we need for this section.
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