## G13

Nare Arakelian Dis 3E
Posts: 58
Joined: Thu Jul 11, 2019 12:16 am

### G13

To prepare a fertilizer solution, a florist dilutes 1.0 L of
0.20 m NH4NO3(aq) by adding 3.0 L of water. The florist then adds
100. mL of the diluted solution to each plant. How many moles of
nitrogen atoms will each plant receive? Solve this exercise without
using a calculator.

I used M1V1=M2V2 to find the concentration of NH4NO3 (0.05 M), but I am struggling with finding the moles of nitrogen atoms. I know the volume is 0.100 L, but I am not sure what concentration to use. Can someone explain?

Harry Zhang 1B
Posts: 101
Joined: Sat Sep 14, 2019 12:16 am

### Re: G13

One thing to keep in mind is that the moles of solute never change. So to find out how many moles of solute are in the solution, we multiply 0.2 M by 1.0, which indicates that there are 0.2 moles of ammonium nitrate molecules. In this case, you final volume would be 1 L + 3 L, Which equals to 4 L. Divide 0.2 moles by 4 L= 0.05 M. Up to this point, your calculation is correct and you were wondering what concentration to use. In this case, we will use 0.05 M since it's the diluted concentration(adding water to a solution makes it diluted). Finally, we multiply 0.05 mole/L by 0.1 L and you will have your moles of nitrogen atoms, which is 0.005 moles.

Ali Polansky 1A
Posts: 15
Joined: Fri Aug 09, 2019 12:15 am
Been upvoted: 1 time

### Re: G13

0.005 moles is the number of moles each plant receives of NH4NO3. To find moles of N atoms each plant will receive you take 0.005 moles and multiply by the molar ratio (2 moles of N atoms: 1 mole of NH4NO3) so each plant receives 1 x 10^-2 moles of nitrogen atoms.