Would someone be able to explain how to do G19 part b to me?
(b) A sample of 0.366 M HCl(aq)of volume 25.00 mL is drawn from a reagent bottle with a pipet. The sample is transferred to a flask of volume 125.00 mL and diluted to the mark with water. What is the molar concentration of the dilute hydrochloric acid solution?
i used the equation M(initial)V(initial)=M(final)V(final) to get (.366)(.025)=(x)(.025+.125) and got .0244M but this is incorrect and im not sure why
G19
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Re: G19
When they say the sample is transferred to a flask or container of X volume, your second volume for your calculation is only X. You don't need to add the original sample volume. So basically, don't add anything to the 125 ml. Hope this helps!
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Re: G19
Your original concentration was 0.366 mol/L, meaning that if you took out 25 mL you would have 0.00915 moles. Then, 0.00915 moles/.125 L, because the total volume is 125 mL, not 125 + 25 mL, since the volume flask cannot exceed 125 mL, giving you a 0.0732 M. Hope this helps!
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