G19

[emmaferry2D]

Would someone be able to explain how to do G19 part b to me?
(b) A sample of 0.366 M HCl(aq)of volume 25.00 mL is drawn from a reagent bottle with a pipet. The sample is transferred to a flask of volume 125.00 mL and diluted to the mark with water. What is the molar concentration of the dilute hydrochloric acid solution?
i used the equation M(initial)V(initial)=M(final)V(final) to get (.366)(.025)=(x)(.025+.125) and got .0244M but this is incorrect and im not sure why

[Sarah_Hoffman_2H]

The volume of the dilute solution should just be 125ml, not the initial volume plus 125ml

[rita_debbaneh2G]

When they say the sample is transferred to a flask or container of X volume, your second volume for your calculation is only X. You don't need to add the original sample volume. So basically, don't add anything to the 125 ml. Hope this helps!

[Bella Bursulaya 3G]

Your original concentration was 0.366 mol/L, meaning that if you took out 25 mL you would have 0.00915 moles. Then, 0.00915 moles/.125 L, because the total volume is 125 mL, not 125 + 25 mL, since the volume flask cannot exceed 125 mL, giving you a 0.0732 M. Hope this helps!