Intro to O Chem pg153

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Adriana Juarez 1
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Joined: Fri Sep 25, 2015 3:00 am

Intro to O Chem pg153

Postby Adriana Juarez 1 » Mon Feb 22, 2016 9:19 pm

On this page there is an example with propene+HBr.

I understand that the double bond between C=C breaks to supply electrons for Hydrogen, but after that how do you know that only CH obtains a positive charge? If CH2 and CH are both losing two electrons, how do you know that CH is the one with the positive charge and the H+ from HBr attaches to the CH2 molecule?

Ronald Yang 2F
Posts: 86
Joined: Fri Sep 25, 2015 3:00 am

Re: Intro to O Chem pg153

Postby Ronald Yang 2F » Mon Feb 22, 2016 9:33 pm

When the double bond "attacks" the partially positive H, essentially the electrons from the H-Br bond will go to the Br, meaning that when that H makes a bond with one of the carbon atoms, in this case being the carbon on the end because we want to put the positive charge on the carbon that is more stable (carbon with two carbons attached is more stable than carbon with one carbon attached because of delocalization of charge due to more carbons around a central carbon). Thus, the carbocation is the carbon in the middle.

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