Slow Step Determining Overall Rate

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TeaK1C
Posts: 17
Joined: Fri Sep 25, 2015 3:00 am

Slow Step Determining Overall Rate

Postby TeaK1C » Sun Feb 28, 2016 6:43 pm

Im still a little confused on the concept of the slow step, i know that the slow step determines the overall rate for the reaction. So for example if the first step in a reaction involves breaking two bonds, is the fact that there were two bonds involved the reason why the overall rate is second order?

If that is the case, is that always the rule? So if there were three bonds being broken/formed then the overall reaction would be third order?

Amy Wong 1I
Posts: 23
Joined: Fri Sep 25, 2015 3:00 am

Re: Slow Step Determining Overall Rate

Postby Amy Wong 1I » Sun Feb 28, 2016 10:21 pm

The slow step is always given to you, so you don't have to try to find out which is the slow step yourself. Orders are not determined by how many bonds there are, but have to do with the coefficients of the reactants.


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