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In the first step of this reaction mechanism, does the hydrogen have to form a bond with carbon 3? Because I don't see why it couldn't also do the same with carbon 2 instead. The reaction can be found on pg 152 in the organic textbook.
Yes, it could, but for reasons we haven't discussed yet the hydrogen will almost always form a bond with the terminal or end carbon. This puts the positive charge on the more substituted secondary carbon, which is more stable.
I was also thinking the same thing: whether it can be written as CH3-CHBr-CH3 as opposed to CH3-CH2-CH2Br.
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