2013 5C

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2013 5C

Postby AvaM1c » Thu Mar 10, 2016 11:26 pm

Why do you not use the double bond on (Z)-2-iodobut-2-enol as a nucleophile and use the NH as a nucleophile instead? Basically why does the negative atom get a higher priority of being a nucleophile?

also for the second part when it asks what type of reaction this is, how do you know it is SN2?

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Joined: Fri Sep 25, 2015 3:00 am

Re: 2013 5C

Postby annchen0628 » Fri Mar 11, 2016 2:47 pm

NH has a fully negative charge and OH is only partially negative. It's electronegative. NH therefore is more nucleophilic. It's SN2 because it's bimolecular. Two reactants are involved in the reaction. It's substitution because it's not "added" on to a double bond.

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