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Postby mrao25 » Sun Feb 21, 2016 3:16 pm

Besides the fact that it would fit the equation, if delta G is positive and delta H is positive, why is delta S negative for activation? That is to say, what is the molecular reason? Does it have to do with microstates?


Shaye Busse 3B
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Joined: Fri Sep 25, 2015 3:00 am

Re: Entropy

Postby Shaye Busse 3B » Sun Feb 21, 2016 5:17 pm

The reason the delta S is a negative value for reactants to a transition state is because the transition state is actually more stable than the reactants. This is because the reactants are connected by hybrid bonds in the transition state, reducing the total number of molecules in the system. This reduction in the number of molecules in the system reduces the entropy of the system because it has become more stable.

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