4.29 Green book
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4.29 Green book
On the bottom of page 85 of the course reader, how do you know that Step 1 is slower and has a higher activation energy than step two? Can someone apply this to 4.29 in the green book? Will the reaction profile always look like this?
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Re: 4.29 Green book
Ea1>Ea2 because step 1 involves breaking two bonds whereas step 2 is the formation of one bod. Therefore k1<k2
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Re: 4.29 Green book
Breaking bonds has higher activation energy than forming bonds. The step with the highest activation energy is the slowest.
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Re: 4.29 Green book
this can be seen in the arrhenius equation:
https://www.chemguide.co.uk/physical/basicrates/arrhenius.html
https://www.chemguide.co.uk/physical/basicrates/arrhenius.html
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