Relation between k and activation energy

[Mishta Stanislaus 1H]

What exactly is the relationship between k and activation energy?

[Lily Sperling 1E]

You can observe the relationship through the Arrhenius Equation - basically, the formula implies that the rate constant increases exponentially as the activation energy decreases.

[Christina Cen 2J]

Reactions generally speed up when temperature increases and slow down when temperature decreases. This means that k increases with increasing temperature, which in turn increases the overall rate of the reaction.

[diangelosoriano]

If a catalyst were added, how would this also affect k or activation energy?

[Johann Park 2B]

If a catalyst were added, how would this also affect k or activation energy?

When you add a catalyst, the reaction is sped up - k is increased and E_a is lowered. The new pathway has a lower activation energy.

[Nehal Banik]

As activation energy decreases, it reduces the energy barrier required for the reaction to proceed therefore the rate constant increases, causes the overall rate of the reaction to increase. Also, if the activation energy is higher, the dependence of the rate constant on temperature increases, meaning at higher temperatures the rate constant is most likely going to be higher. These are a couple of the relationships that can be understood from the Arrhenius equation in the textbook.
Hope that helps!

[Mai V 4L]

Anyone have a video they think is a good reference for this topic?

[Joshua Eidam 2A]

If a catalyst were added, how would this also affect k or activation energy?

Adding a catalyst is going to decrease the activation energy, E_a, which will ultimately lead to an increase in the rate constant k.

[Joshua Eidam 2A]

A clear way to look at the relationship between k and the activation energy, E_a, is through the Arrhenius equation, . This equation shows how a decrease in activation energy would ultimately lead to an increase in k and vice versa. Hope this helps!

[005502505]

Using the equation k= Ae^-Ea/RT, you can determine that adding a catalyst will decrease the activation energy (Ea); with a decrease of Ea comes an increase in k, the rate constant.

[Kathryn Heinemeier 3H]

When a catalyst is added, the activation energy will decrease while the rate constant, k will increase.